我试图在两个耳机中收听2声道音频(左右耳机中的音频相同)。
现在的情况:
Slider居中-效果很好(两个耳机中的两个通道)。
滑块在右侧-效果很好(两个耳机都位于右侧声道)。
滑块在左侧-不起作用(仅左侧耳机中的左声道)。
const splitter = wavesurfer.backend.ac.createChannelSplitter(2);
const merger = wavesurfer.backend.ac.createChannelMerger(2);
const leftGain = wavesurfer.backend.ac.createGain();
const rightGain = wavesurfer.backend.ac.createGain();
const panner = wavesurfer.backend.ac.createPanner();
splitter.connect(leftGain, 0);
splitter.connect(rightGain, 1);
leftGain.connect(merger, 0, 0);
rightGain.connect(merger, 0, 1);
merger.connect(panner);
let slider = document.querySelector('#Slider');
$(slider ).change(function () {
rightGain.gain.value = Number(slider.value);
leftGain.gain.value = 1- (Number(slider.value));
})
wavesurfer.backend.setFilters([splitter, leftGain, rightGain, merger]);
当滑杆在左侧时,我只想在两个耳机中听到左声道。有人能帮我吗?
调用setFilters()时, waversurfer.js将以简单链连接所有提供的节点。在您的情况下,这意味着它将创建其他连接,如下所示:
splitter.connect(leftGain);
leftGain.connect(rightGain);
rightGain.connect(merger);
这可能不是您想要的。但是可以利用这种行为。我修改了您的示例。
const input = wavesurfer.backend.ac.createGain();
const splitter = wavesurfer.backend.ac.createChannelSplitter(2);
const merger = wavesurfer.backend.ac.createChannelMerger(2);
const leftGain = wavesurfer.backend.ac.createGain();
const rightGain = wavesurfer.backend.ac.createGain();
// This will make sure that a mono signal gets upmixed to stereo.
// If you always have stereo sound you can remove it.
input.channelCountMode = 'explicit';
// It is only necessary to connect the right channel
// because this is the one which needs optional parameters.
splitter.connect(rightGain, 1);
rightGain.connect(merger);
rightGain.connect(merger, 0, 1);
// Only the one connection which needs an optional parameter
// needs to be done for the left channel
leftGain.connect(merger, 0, 1);
// wavesufer.js will connect everything else.
wavesurfer.backend.setFilters([ input, splitter, leftGain, merger ]);
我还添加了另一个GainNode作为第一个节点,以确保在单声道的情况下将信号上混为立体声。我删除了PannerNode,因为在您的示例中未使用它。
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