我想要的是
我正在处理一个django表单，它需要输入密码。我需要传递多个正则表达式的输入值，这将测试是否：
我想知道其中哪些条件已得到满足，哪些没有得到满足。
我做了什么
def clean_password(self):
password = self.cleaned_data.get("password")
regexes = [
"[a-z]",
"[A-Z]",
"[0-9]",
#other regex...
]
# Make a regex that matches if any of our regexes match.
combined = "(" + ")|(".join(regexes) + ")"
if not re.match(combined, password):
print("Some regex matched!")
# i need to pass in ValidationError those regex that haven't match
raise forms.ValidationError('This password does not contain at least one number.')
虽然您可以在此处使用正则表达式，但我会坚持使用普通的Python：
from string import ascii_uppercase, ascii_lowercase, digits, punctuation
from pprint import pprint
character_classes = {'lowercase letter': ascii_lowercase,
'uppercase letter': ascii_uppercase,
'number': digits,
'special character': punctuation # change this if your idea of "special" characters is different
}
minimum_length = 8
def check_password(password):
long_enough = len(password) >= minimum_length
if not long_enough:
print(f'Your password needs to be at least {minimum_length} characters long!')
result = [{class_name: char in char_class for class_name, char_class in character_classes.items()} for char in password]
result_transposed = {class_name: [row[class_name] for row in result] for class_name in character_classes}
for char_class, values in result_transposed.items():
if not any(values):
# Instead of a print, you should raise a ValidationError here
print(f'Your password needs to have at least one {char_class}!')
return result_transposed
check_password('12j3dSe')
输出：
Your password needs to be at least 8 characters long!
Your password needs to have at least one special character!
这使您可以更灵活地修改密码要求，以防万一您想说“您需要此字符类的X”。
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