我有一个清单l = [1, 2, 3]
,我想要l[2->infinity] == 3
。基本上看起来像[1, 2, 3, 3, 3, 3, ...]
。我试过了:
[1, 2, *3]
要么
[1, 2, 3, ...]
无论如何,是否要为一系列索引添加“默认元素”?
澄清度
我不想重复元素n
时间,因为我无法在列表的长度之外进行索引。我实际上想为的所有索引提供一个值2->infinity
。该索引范围的某种默认值。
除了克里斯回答,您可以创建自己的生成器:
def inf3():
yield 1
yield 2
while True:
yield 3
>>> g = inf3()
>>> [next(g) for _ in range(100)]
[1, 2, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3]
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