我正在尝试使用一种通用方法来AlamofireObjectMapper发送请求，其中输入是BasicMappable（通用类型），输出是响应
func sendRequest<T>(endPoint: String,
parameters: Parameters,
method: HTTPMethod,
mappingObject: T.Type) -> T where T : BaseMappable {
var answer = T.self
Alamofire.request(applicationBaseURL + endPoint,
method: method,
parameters: parameters,
headers: nil)
.responseObject { ( response: DataResponse<T>) in
let data = response.result.value
answer = data as! T.Type
}
return answer as! T
}
所以我在VC中使用这种方法：
let authResponse = requestHelper.sendRequest(endPoint: "/auth/users/create/",
parameters: params,
method: .post,
mappingObject: AnswerClass.self)
而且它构建良好。但是，当我尝试发送请求时，出现了崩溃和错误
Could not cast value of type 'Travel.AuthController.AnswerClass.Type' (0x110186bf8) to 'Travel.AuthController.AnswerClass' (0x10de153b0).
2019-04-15 18:42:28.811494+0300 Travel[9951:596186] Could not cast value of type 'Travel.AuthController.AnswerClass.Type' (0x110186bf8) to 'Travel.AuthController.AnswerClass' (0x10de153b0).
我已经在VC中做到了这一点
Alamofire.request(applicationBaseURL + "/auth/users/create/",
method: .post,
parameters: params,
headers: nil)
.responseObject { (response: DataResponse<AnswerClass>) in
let loginRespone = response.result.value
for error in loginRespone?.errors ?? [] {
print(error.detail)
print(error.source)
print(error.status)
}
而且效果很好
但是我想让这种方法在整个项目中通用
如何正确地转换这些类型的值或还有其他方法？
您需要使用completionHandler以下方法获取对象，
func sendRequest<T>(endPoint: String,
parameters: Parameters,
method: HTTPMethod,
mappingObject: T.Type,
completion: (T?, Error?) -> Void) {
Alamofire.request(applicationBaseURL + endPoint,
method: method,
parameters: parameters,
headers: nil)
.responseObject { ( response: DataResponse<T>) in
switch response.result {
case .success(let value):
completion(value, nil)
case .failure(let error):
completion(nil, error)
}
}
}
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我来说两句