如何从该数组中过滤重复值?
实际上,对于country
和city
,数据是相同的-除了总体发生变化之外。
如何删除包含更高人口的阵列?
$arr = array
(
"100" => array(
array(
"country" => 'France',
"city" => 'Paris',
"population" => '1800000',
),
array(
"country" => 'France',
"city" => 'Paris',
"population" => '2000000',
),
array(
"country" => 'France',
"city" => 'Toulouse',
"population" => '500000',
),
)
"101" => array(
array(
"country" => 'Russia',
"city" => 'Moscow',
"population" => '144000000',
)
)
);
因此,所需的输出应为:
$arr = array
(
"100" => array(
array(
"country" => 'France',
"city" => 'Paris',
"population" => '1800000'
),
array(
"country" => 'France',
"city" => 'Toulouse',
"population" => '500000'
),
)
"101" => array(
array(
"country" => 'Russia',
"city" => 'Moscow',
"population" => '144000000',
)
)
);
这是我尝试的:
$temp_array = [];
foreach ($array as &$v) {
if (!isset($temp_array[$v['country']] && $temp_array[$v['city']]))
$temp_array[$v[$key]] =& $v;
}
$array = array_values($temp_array);
return $array;
您可以首先使用array_reduce过滤较低的人口(使用国家和城市的组合作为关键字)。然后将其爆炸并使用该最小值重置数组:
foreach($arr as $k => &$ar) {
$temp = array_reduce($ar, function ($carry, $item) {
$key = $item["country"] . "###" . $item["city"];
$carry[$key] = (isset($carry[$key]) && $item["population"] > $carry[$key]) ? $carry[$key] : $item["population"];
return $carry;
}, []);
$ar = [];
foreach($temp as $k => $val) {
list($country, $city) = explode("###", $k);
$ar[] = array("country" => $country, "city" => $city, "population" => $val);
}
}
直播示例:3lv4
编辑:
您可以使用array_filter
,而不是foreach
循环,以避免应对:
$ar = array_filter($ar, function ($item) use ($mins) {
$key = $item["country"] . "###" . $item["city"];
return $mins[$key] == $item["population"];
});
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