如何在BigQuery（标准SQL）中实现“ LIKE ANY”？

责任HL

我想使用“像任何人一样”的功能。但是，BigQuery无法识别“ ANY”运算符。有什么功能可以代替“ LIKE ANY”吗？

Bigquery-标准SQL

    SELECT
      date,
      CONCAT(fullvisitorid, CAST(visitid AS string)) ord_browsers,
      hits.appInfo.landingScreenName,
      channelgrouping,
      trafficSource.source,
      trafficSource.medium,
      CASE
        WHEN channelgrouping = 'seo_brand' THEN 'Branded'
        WHEN hits.appInfo.landingScreenName LIKE '%/article%'
      OR hits.appInfo.landingScreenName LIKE '%/p/%' THEN 'ADS'
        WHEN (hits.appInfo.landingScreenName LIKE ANY ('%/damesmode/%',  '%/herenkleding/%',  '%/kinderkleding/%',  '%/sportkleding/%')) THEN 'Plist'
        ELSE 'rest'
      END Landing_page
    FROM
      `meta-geography-145406.81187684.ga_sessions_*`,
      UNNEST(hits) AS hits
    WHERE
      (_table_suffix BETWEEN '20190201'
        AND '20190207')

语法错误：[12:47]处出现意外关键字ANY

费利佩·霍法

具有相同问题的更简单查询：

WITH table AS (
  SELECT 'XXXX/herenkleding/XXX' x
)

SELECT x
FROM TABLE
WHERE x LIKE ANY ( 
  '%/damesmode/%'  '%/herenkleding/%',  '%/kinderkleding/%',  '%/sportkleding/%'
)

Syntax error: Unexpected keyword ANY at [2:6]

备选方案1：替换为一系列“喜欢或”

SELECT x
FROM TABLE
WHERE (x LIKE '%/damesmode/%' 
OR x LIKE '%/herenkleding/%'
OR x LIKE '%/kinderkleding/%'
OR x LIKE'%/sportkleding/%')

XXXX/herenkleding/XXX

备选方案2：合并为一个正则表达式

WITH table AS (
  SELECT 'XXXX/herenkleding/XXX' x
)

SELECT x
FROM TABLE
WHERE REGEXP_CONTAINS(x
  , '/(damesmode|herenkleding|kinderkleding|sportkleding)/')

XXXX/herenkleding/XXX

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