我有带属性的对象数组。我想根据乐队分组
我尝试了_groupBy，但未能获得预期的结果
var data=[
{
"tOffice": 123,
"cType": 5000,
"band": -4877,
"minCh": 12,
"maxCh": 20
},
{
"tOffice": 123,
"cType": 5000,
"band": -4877,
"minCh": 1,
"maxCh": 2
},
{
"tOffice": 123,
"cType": 5000,
"band": -4877,
"minCh": 11,
"maxCh": 12
},
{
"tOffice": 123,
"cType": 6000,
"band": -5877,
"minCh": 11,
"maxCh": 12
},
{
"tOffice": 456,
"cType": 5000,
"band": -4544,
"minCh": 12,
"maxCh": 20
},
{
"tOffice": 456,
"cType": 5000,
"band": -4544,
"minCh": 10,
"maxCh": 11
},
{
"tOffice": 456,
"cType": 6000,
"band": -5211,
"minCh": 12,
"maxCh": 20
},
{
"tOffice": 456,
"cType": 6000,
"band": -5211,
"minCh": 12,
"maxCh": 20
},
{
"tOffice": 456,
"cType": 6000,
"band": -5211,
"minCh": 12,
"maxCh": 20
}
];
预期产量：
var expectedResult = [{
tOffice: 123,
bandType: [{
band: '123-5000',
minMaxCharge: [{
minCh: 12,
maxCh: 20
}, {
minCh: 1,
maxCh: 2
}, {
minCh: 11,
maxCh: 12
}]
},
{
band: '123-6000',
minMaxCharge: [{
minCh: 11,
maxCh: 12
}]
}
]
}, {
tOffice: 456,
bandType: [{
band: '456-5000',
minMaxCharge: [{
minCh: 12,
maxCh: 20
}, {
minCh: 10,
maxCh: 11
}]
},
{
band: '456-6000',
minMaxCharge: [{
minCh: 12,
maxCh: 20
}, {
minCh: 12,
maxCh: 20
}]
}
]
}]
预期结果应包含一个tOffice，最多包含2个组合（5000和6000），band为tOffice + cType的组合。
_.chain(data).groupBy("band").map(function(v, i) {
return {
}
})
我尝试了一些ES6方式，发现lodash方法将是一个不错的选择，但是我不知道
这是一个Vanila js解决方案。您可以使用reduce和做类似的事情Object.values
var data=[{"tOffice":123,"cType":5000,"band":-4877,"minCh":12,"maxCh":20},{"tOffice":123,"cType":5000,"band":-4877,"minCh":1,"maxCh":2},{"tOffice":123,"cType":5000,"band":-4877,"minCh":11,"maxCh":12},{"tOffice":123,"cType":6000,"band":-5877,"minCh":11,"maxCh":12},{"tOffice":456,"cType":5000,"band":-4544,"minCh":12,"maxCh":20},{"tOffice":456,"cType":5000,"band":-4544,"minCh":10,"maxCh":11},{"tOffice":456,"cType":6000,"band":-5211,"minCh":12,"maxCh":20},{"tOffice":456,"cType":6000,"band":-5211,"minCh":12,"maxCh":20},{"tOffice":456,"cType":6000,"band":-5211,"minCh":12,"maxCh":20}];
const merged = data.reduce((r,{tOffice, cType, minCh, maxCh})=>{
const office = r[tOffice] = r[tOffice] || {tOffice, bandType:{}};
const band = `${tOffice}-${cType}`
const nested = office.bandType[band]
= office.bandType[band] || {band, minMaxCharge:[]};
nested.minMaxCharge.push({minCh, maxCh})
return r
},{})
const final = Object.values(merged);
final.forEach(a => a.bandType = Object.values(a.bandType))
console.log(final)本文收集自互联网，转载请注明来源。
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