如何在python中的字典中具有两个键和一个值

130

约翰努

我正在制作一个使用简单字典存储帐户名和密码的小型登录系统。我想知道是否有可能使用电子邮件和用户名，然后使用对两者都有效的密码。例如，我唯一的帐户是密码为“ h1”的“ hello”，我如何才能使密码为“ h1”的“ [email protected]”或“ hello”解锁？

accounts = {'hello':'h1'}
print(accounts)
started = ""
while started != "q":
    started = input("Are you a registered user y/n: (if you want to quit press any key)")  

if started == "n": 
     createLogin = input("Create your desired login name: ")

     if createLogin in accounts: 
         print ("Login name already exist!")
     else:
         createPassw = input("Create your desired password password: ")
         accounts[createLogin] = createPassw
         print("User created!")
         addemail = input("What is your email address :")
         accounts[createLogin].append(addemail)             

elif started == "y": 
    login = input("Enter your login name: ")

    if login in accounts:
        passw = input("Enter your password")

    else:
        print("user doesnt exist.")




    if login in accounts and accounts[login] == passw:
        print("Login successful!")
        changepassword = input("Would you like to change your password?")
        if changepassword in ["Y", "y"]:
            newpassw = input("What do you want your new password to be?")
            accounts[login] = newpassw
            print("password succesfully changed!")
        else:
            print("Password was not changed.")
    else:
        print("Incorrect password!")

我试图将电子邮件添加到用户名，以便字典看起来像{['hello @ mail.com，'hello']：'h1'}。有任何想法吗？

弥撒

你是说这里

     accounts[createLogin].append(addemail)

那当然是行不通的，因为值是string，而string没有.append。同样，将电子邮件附加到密码上也不会很紧张。

我认为这不是一个好的结构： {['[email protected],'hello']:'h1'}

我会accounts列出一些字典：

accounts = [
    {
        'email': '[email protected]', 
        'username': 'hello', 
        'password': 'h1',
    },
]

然后，您可以查看是否有具有给定用户名或电子邮件的帐户（我将使用function，希望可以）：

def find_account_by_login(accounts, login):
    for account in accounts:
        if account['email'] == login or account['username'] == login:
            return account
    # no account matched the login
    return None

elif started == "y": 
    login = input("Enter your login name: ")
    account = find_account_by_login(accounts, login)
    if not account:
        print("user doesnt exist.")
    else:
        passw = input("Enter your password")
        if passw != account['password']:
            print("Incorrect password!")
        else:
            print("Login successful!")
            # change the password...

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