我已经写了一个脚本来street-address从json响应中获取es，但是我无法到达那部分。对我来说结构似乎有些复杂。
包含street-addresses的响应块：
[[44189579,25735941,-80305513,"$640K",1,0,0,0,["$640K",4,3.0,1963,false,null,"6,000 sqft lot","","ForSale","For Sale by Owner",0,{"zpid": 44189579,"streetAddress": "6811 SW 38th St","zipcode": "33155","city": "Miami","state": "FL","latitude": 25.735941,"longitude": -80.305513,"price": 640000.0,"dateSold": 0,"bathrooms": 3.0,"bedrooms": 4.0,"livingArea": 1963.0,"yearBuilt": -1,"lotSize": 6000.0,"homeType": "SINGLE_FAMILY",
到目前为止，我已经尝试过：
import requests
url = "https://www.zillow.com/search/GetResults.htm?spt=homes&status=100000<=111101&ht=100000&pr=,&mp=,&bd=0%2C&ba=0%2C&sf=,&lot=0%2C&yr=,&singlestory=0&hoa=0%2C&pho=0&pets=0&parking=0&laundry=0&income-restricted=0&fr-bldg=0&condo-bldg=0&furnished-apartments=0&cheap-apartments=0&studio-apartments=0&pnd=0&red=0&zso=0&days=any&ds=all&pmf=0&pf=0&sch=100111&zoom=11&rect=-80419407,25712692,-80201741,25759392&p=1&sort=days&search=map&rid=72458&rt=7&listright=true&isMapSearch=1&zoom=11"
res = requests.get(url,headers={"User-Agent":"Mozilla/5.0"})
print(res.json()['map']['properties'])
预期成绩：
6811 SW 38th St
等等.....
@ ebro42是正确的，获取数据的最佳方法是递归地遍历json数据对象。我认为他的建议可以通过不依赖于传递的回调容器而改为使其成为您迭代的生成器而得到改善。
from typing import Iterable
def get_by_key(key: str, collection: Iterable):
if isinstance(collection, dict):
for k, v in collection.items():
if k == key:
yield v
elif isinstance(v, Iterable) and not isinstance(v, str):
yield from get_by_key(key, v)
elif isinstance(collection, Iterable) and not isinstance(collection, str):
for i in collection:
yield from get_by_key(key, i)
for address in get_by_key('streetAddress', res.json()):
print(address)
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我来说两句