使用python的xml展平

goten 发表于 Dev

天沟

我正在尝试展平xml并写入csv，以便可以由etl进程使用它。

<Answers>
      <AnswersList>
        <Entry key="qs_location_name" type="System.String">
          <value>Location Name</value>
        </Entry>
        <Entry key="qs_location_riskAddress1" type="System.String">
          <value>Risk Address 1</value>
        </Entry>
        <Entry key="qs_location_riskAddress2" type="System.String">
          <value>Risk Address 2</value>
        </Entry>
</AnswersList>
</Answers>

我的代码如下

from lxml import etree
from io import StringIO
tree = etree.parse(StringIO(xml_file))

root = tree.getroot().tag
for node in tree.iter():
    for child in node.getchildren():
        if child.text:
          if child.text.strip():
            print("{}.{} = {}".format(root, ".".join(tree.getelementpath(child).split("/")), child.text.strip()))

上面的代码提供以下输出。

AustraliaBizPackProposal.Answers.AnswersList.Entry[1].value = Location Name
AustraliaBizPackProposal.Answers.AnswersList.Entry[2].value = Risk Address 1
AustraliaBizPackProposal.Answers.AnswersList.Entry[3].value = Risk Address 2

我的预期输出是如下生成的，请告知

AustraliaBizPackProposal.Answers.AnswersList.qs_location_name.value = Location Name
AustraliaBizPackProposal.Answers.AnswersList.qs_location_riskAddress1.value = Risk Address 1
AustraliaBizPackProposal.Answers.AnswersList.qs_location_riskAddress2.value = Risk Address 2

Rodwan Bakkar |

此代码适用于此特定文件：

root = tree.getroot().tag
for node in tree.iter():
for child in node.getchildren():
    if child.tag == 'Entry':            
        path = tree.getelementpath(child).split("/")[0]
        key = child.attrib['key']
        for val in child.getchildren(): 
            try:                    
                print("{}.{}.{}.{} = {}".format(root, path, key, val.tag, val.text.strip()))
            except:
                print("{}.{}.{}.{} = {}".format(root, path, key, val.tag, val.attrib['Text']))

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