我对python很陌生,我试图在列中输出多个列表,一个在另一个列表下,我不知道。
我当前的输出是:
Name, Count, Correct, Incorrect, Accuracy, Total
Abena 3 3 0 100 45
Malcolm 1 1 0 100 1
Jane 1 1 0 100 20
Liz 1 1 0 100 10
Andy 1 0 1 0 20
Sandip 0 0 0 0 0
如何将数字分成单独的列?
当前要打印的代码是:
CoinFile = open("CoinCount.txt", "r")
print("Name, Count, Correct, Incorrect, Accuracy, Total")
for record in VolunteersToSort:
print(record[0] + " " + record[1]+ " " + record[2] + " " + record[3] + " " + record[4] + " " + record[5] )
文件内容:
['Abena', '3', '3', '0', '100', '45']
['Malcolm', '1', '1', '0', '100', '1']
['Jane', '1', '1', '0', '100', '20']
['Andy', '1', '0', '1', '0', '20']
['Sandip', '0', '0', '0', '0', '0']
['Liz', '1', '1', '0', '100', '10']
header = ['Name', 'Count', 'Correct', 'Incorrect', 'Accuracy', 'Total']
my_list = [
['Abena', '3', '3', '0', '100', '45'],
['Malcolm', '1', '1', '0', '100', '1'],
['Jane', '1', '1', '0', '100', '20'],
['Andy', '1', '0', '1', '0', '20'],
['Sandip', '0', '0', '0', '0', '0'],
['Liz', '1', '1', '0', '100', '10']
]
print("{: >10} {: >10} {: >10} {: >10} {: >10} {: >10}".format(*header))
for row in my_list:
print("{: >10} {: >10} {: >10} {: >10} {: >10} {: >10}".format(*row))
您将输出为:
Name Count Correct Incorrect Accuracy Total
Abena 3 3 0 100 45
Malcolm 1 1 0 100 1
Jane 1 1 0 100 20
Andy 1 0 1 0 20
Sandip 0 0 0 0 0
Liz 1 1 0 100 10
您可以根据需要编辑列长。这里使用10。
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