如何创建一个函数来获取特定字符串的前后7个单词？

neo33 发表于 Dev

neo33

您好，我想制作一个javascript函数，将数学运算前后的7个单词返回给特定的关键字

我尝试如下：

function myFunction(text) {

    b=text.match("(?:[a-zA-Z'-]+[^a-zA-Z'-]+){0,7}"+text+"(?:[^a-zA-Z'-]+[a-zA-Z'-]+){0,7}");

    return b;

但是，当我搜索文本“创建”时，我得到了：

create

我想要的输出将是：

the Community, and view patterns you create or favorite in My Patterns. Explore results

我的完整代码如下所示，带有对应的名为Text的字符串，因此，我要感谢支持克服此任务的支持。

<!DOCTYPE html>
<html>
<body>

<p id="demo"></p>
<script>


var Text='RegExr was created by gskinner.com, and is proudly hosted by Media Temple. Edit the Expression & Text to see matches. Roll over matches or the expression for details. PCRE & Javascript flavors of RegEx are supported. The side bar includes a Cheatsheet, full Reference, and Help. You can also Save & Share with the Community, and view patterns you create or favorite in My Patterns. Explore results with the Tools below. Replace & List output custom results. Details lists capture groups. Explain describes your expression in plain English.'
function myFunction(text) {

    b=text.match("(?:[a-zA-Z'-]+[^a-zA-Z'-]+){0,7}"+text+"(?:[^a-zA-Z'-]+[a-zA-Z'-]+){0,7}");

    return b; 
}
document.getElementById("demo").innerHTML = myFunction("create");
</script>

</body>
</html>

艾略特B.

对于这种类型的任务，正则表达式不是一个很好的工具。我建议您使用split将您的句子分解成单词数组，然后indexOf找到匹配的单词并打印相邻的单词。

这是一个工作示例：

let sentence = "blah blah blah the Community, and view patterns you create or favorite in My Patterns. Explore results blah blah blah";
let words = sentence.split(" ");
let index = words.indexOf("create");
let result = [];

if (index > -1) {     
    for (i=index-7; i < (index+8); i++) {
        result.push(words[i]);
    }
}
    
console.log(result.join(" "));

这就是要点，但是您需要修改我的代码示例以考虑边缘情况（即，多个匹配单词，在匹配单词之前/之后少于7个单词）。

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