我开始学习JAXB,所以我的问题可能很愚蠢。现在我有了类,想要生成XML Schema。在执行此指令后,我得到了异常
IllegalAnnotationExceptions ...没有无参数的默认构造函数。
是的 我的课程没有默认的无参数构造函数。太简单了 我有类与包可见的构造函数/ final方法和偏离路线的参数。我该怎么做-创建一些特定的momemto / builder类或将我的构造函数指定为JAXB(以什么方式?)?谢谢。
JAXB可以使用XML适配器来支持这种情况。考虑您具有以下对象,没有零参数构造函数:
package blog.immutable;
public class Customer {
private final String name;
private final Address address;
public Customer(String name, Address address) {
this.name = name;
this.address = address;
}
public String getName() {
return name;
}
public Address getAddress() {
return address;
}
}
您只需要创建此类的可映射版本:
package blog.immutable.adpater;
import javax.xml.bind.annotation.XmlAttribute;
import blog.immutable.Address;
public class AdaptedCustomer {
private String name;
private Address address;
@XmlAttribute
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Address getAddress() {
return address;
}
public void setAddress(Address address) {
this.address = address;
}
}
还有一个在它们之间转换的XML适配器:
package blog.immutable.adpater;
import javax.xml.bind.annotation.adapters.XmlAdapter;
import blog.immutable.Customer;
public class CustomerAdapter extends XmlAdapter<AdaptedCustomer, Customer> {
@Override
public Customer unmarshal(AdaptedCustomer adaptedCustomer) throws Exception {
return new Customer(adaptedCustomer.getName(), adaptedCustomer.getAddress());
}
@Override
public AdaptedCustomer marshal(Customer customer) throws Exception {
AdaptedCustomer adaptedCustomer = new AdaptedCustomer();
adaptedCustomer.setName(customer.getName());
adaptedCustomer.setAddress(customer.getAddress());
return adaptedCustomer;
}
}
然后,对于引用Customer类的属性,只需使用@XmlJavaTypeAdapter批注:
package blog.immutable;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.adapters.XmlJavaTypeAdapter;
import blog.immutable.adpater.CustomerAdapter;
@XmlRootElement(name="purchase-order")
public class PurchaseOrder {
private Customer customer;
@XmlJavaTypeAdapter(CustomerAdapter.class)
public Customer getCustomer() {
return customer;
}
public void setCustomer(Customer customer) {
this.customer = customer;
}
}
有关更详细的示例,请参见:
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