覆盖节点服务器中的文件

亚历克斯·艾恩赛德

因此,在将文件上传到数据库之前,我有一台服务器将文件临时保存在其内存中。这是我的代码:

uploadImage(file, uid, res) {
    var fs = require('fs');
    mongoose.connect(config.db, {useNewUrlParser: true},).catch(e => console.log(e));
    var conn = mongoose.connection;
    Grid.mongo = mongoose.mongo;
    const gfs = Grid(conn.db);
    const writeStream = gfs.createWriteStream({
        filename: file.filename,
    });
    fs.createReadStream(file.path).pipe(writeStream);
    writeStream.on('close', file => {
        const {_id} = file;
        return Account.findByIdAndUpdate(uid, {'employer.logo': _id}).then(() => res.redirect('/employer')).catch(e => console.log(e));
    });
},

我正在尝试优化图像,然后将其上传到数据库,如下所示:

async uploadImage(file, uid, res) {
    const imagemin = require('imagemin');
    const imageminJpegtran = require('imagemin-jpegtran');
    const imageminPngquant = require('imagemin-pngquant');
    console.log(1);
    // const newFilePath = `${file.path}optimized`;
    const newFile = await imagemin([file.path], file.path, {
        plugins: [
            imageminJpegtran(),
            imageminPngquant({quality: '65-80'})
        ]
    });
    // newFile.path = newFilePath;
    console.log(2);
    console.log(file);
    console.log(newFile);
    var fs = require('fs');
    await mongoose.connect(config.db, {useNewUrlParser: true},).catch(e => console.log(e));
    var conn = mongoose.connection;
    Grid.mongo = mongoose.mongo;
    const gfs = Grid(conn.db);
    const writeStream = gfs.createWriteStream({
        filename: newFile.filename,
    });
    fs.createReadStream(newFile.path).pipe(writeStream);
    writeStream.on('close', file => {
        const {_id} = file;
        return Account.findByIdAndUpdate(uid, {'employer.logo': _id}).then(() => res.redirect('/employer')).catch(e => console.log(e));
    });
},

但这告诉我EEXIST: file already exists, mkdir '/home/alex/Documents/Projects/ontario-job-portal/public/images/logos/b80872b65d18d09bb498abcabe2f3f94',这是真的。我正在尝试覆盖之前的图像。

我如何使其覆盖文件?

创建新文件会导致权限被拒绝错误。

编辑。重要

事实证明,imagemin函数返回的对象与前一个对象略有不同。这是我的工作代码:

async uploadImage(file, uid, res) {
    const imagemin = require('imagemin');
    const imageminJpegtran = require('imagemin-jpegtran');
    const imageminPngquant = require('imagemin-pngquant');
    console.log(1);
    const path = require("path");
    const newFilePath = path.dirname(file.path);
    const newFile = await imagemin([file.path], path.dirname(file.path), {
        plugins: [
            imageminJpegtran(),
            imageminPngquant({quality: '65-80'})
        ]
    });
    newFile.path = newFilePath;
    newFile.filename = newFile[0].path.replace(/public\/images\/logos\//, '');
    console.log(newFile.filename);
    var fs = require('fs');
    await mongoose.connect(config.db, {useNewUrlParser: true},).catch(e => console.log(e));
    var conn = mongoose.connection;
    Grid.mongo = mongoose.mongo;
    const gfs = Grid(conn.db);
    console.log(2);
    const writeStream = gfs.createWriteStream({
        filename: newFile[0].filename,
    });
    console.log(3);
    fs.createReadStream(newFile[0].path).pipe(writeStream);
    console.log(4);
    writeStream.on('close', file => {
        console.log(5);
        const {_id} = file;
        return Account.findByIdAndUpdate(uid, {'employer.logo': _id}).then(() => res.redirect('/employer')).catch(e => console.log(e));
    });
},
吉利3

看起来您正在将现有文件的路径提供给imagemin,其中需要目录。要从路径中提取目录,请使用path.dirname(file.path)

const path = require("path");
const newFile = await imagemin([file.path], path.dirname(file.path), {
    ...

请注意,这不会覆盖现有文件。似乎imagemin没有直接支持它。您可以根据需要手动进行操作fs,但是我不确定为什么会这样做您似乎对将这些文件用作临时文件感兴趣。将文件写入mongo后,您可能需要添加一些代码来删除文件。

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