我想问你我是否可以计算案例陈述中的“真实”。
t_1 As (
SELECT *,
-- Spot Guide not to be Empty
CASE
WHEN (total_spots_number <> 0 AND (spot1_availability IS NULL AND spot2_availability IS NULL AND spot3_availability IS NULL)) THEN 'cannot be empty'
WHEN (total_spots_number = 1 AND SUM(spot1_availability IS NOT NULL AND spot2_availability IS NOT NULL AND spot3_availability IS NOT NULL) <> 1) THEN 'one spot is incomplete'
WHEN (total_spots_number = 2 AND SUM(spot1_availability IS NOT NULL AND spot2_availability IS NOT NULL AND spot3_availability IS NOT NULL) <> 2) THEN 'two spots are incomplete'
WHEN (total_spots_number = 3 AND SUM(spot1_availability IS NOT NULL AND spot2_availability IS NOT NULL AND spot3_availability IS NOT NULL) <> 3) THEN 'three spots are incomplete'
ELSE 'nothing to check'
END AS QA_Check_1
FROM Main_Data
)
SELECT * FROM t_1
条件表达式的值是1
如果它是真的,所以你可以简单地添加它们。
WITH availability AS (
SELECT (spot1_availability IS NOT NULL) + (spot2_availability IS NOT NULL) + (spot3_availability IS NOT NULL) AS availability_count
FROM Main_Data
)
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我来说两句