我正在尝试处理如下所示的 json 文件,并以以下输出格式提取其数据以进行进一步处理。
json文件
{
"application_robotics-2.1.610.80350109": [
"/home/machine_process/application_robotics/services/linear_service/4.106.50109987/robotics.yaml",
"/home/machine_process/application_robotics/services/linear_service/4.106.50109987/application_robotics-4.106.50109987.zip"
],
"web_robotics-3.116.50100987": [
"/home/machine_process/application_robotics/services/web_robotics/3.116.50100987/robotics.yaml",
"/home/machine_process/application_robotics/services/web_robotics/3.116.50100987/web_robotics-3.116.50100987.zip"
]
}
预期的输出格式
name = "application_robotics-2.1.610.80350109" # where name is a variable to be used in the other portion of the code.
yaml = "/home/machine_process/application_robotics/services/linear_service/4.106.50109987/robotics.yaml" # where yaml is a variable.
zip = "/home/machine_process/application_robotics/services/linear_service/4.106.50109987/application_robotics-4.106.50109987.zip" # where zip is a variable.
相同的格式适用于其他条目。
下面是我想出的代码片段,我并没有完全理解逻辑。任何帮助在这里都会很有帮助。谢谢。
with concurrent.futures.ProcessPoolExecutor() as executor:
with open(file_path, "r") as input_json:
json_data = json.load(input_json)
for key, value in json_data.items():
name = json_data[key]
yaml = json_data[value]
zip = json_data[value]
file_location = os.path.dirname(tar)
futures = executor.submit(
other_function_name, yaml, zip, file_location, name
)
results.append(futures)
电流输出:
['home/machine_process/application_robotics/services/linear_service/4.106.50109987/robotics.yaml', '/home/machine_process/application_robotics/services/linear_service/4.106.50109987/application_robotics-4.106.50109987.zip']
由于name
对应于按键;yaml
到列表的第一个元素;对于第二个zip_
元素(注意这zip
是一个 python 内置的,所以避免使用它作为变量名),我们可以直接解包它,因为我们循环遍历字典并将它们传递给executor
.
with concurrent.futures.ProcessPoolExecutor() as executor:
with open(file_path, "r") as input_json:
json_data = json.load(input_json)
for name, (yaml, zip_) in json_data.items():
file_location = os.path.dirname(tar)
futures = executor.submit(other_function_name, yaml, zip_, file_location, name)
results.append(futures)
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我来说两句