我正在尝试接受用户输入以将许多行读入文本文件。到目前为止，我遇到了这个错误，但出现此错误：在write_dogs line = f.next（）。strip（）中AttributeError：'_io.TextIOWrapper'对象没有属性'next'
到目前为止，这是我的代码。
def write_dogs():
total_cards = int(input("How many cards do you wish to play with? "))
if total_cards %2 != 0:
print("Please enter an even number")
main_menu()
elif total_cards > 30 or total_cards < 4:
print("Please enter a number less that 30 and more than 4")
main_menu()
else:
N = total_cards
with open("dogs.txt") as f:
with open("dogswrite.txt", "w") as f1:
for i in range(N):
line=f.next().strip()
f1.write(line)
任何帮助，将不胜感激
工作代码如下
def write_dogs():
total_cards = int(input("How many cards do you wish to play with? "))
if total_cards %2 != 0:
print("Please enter an even number")
main_menu()
elif total_cards > 30 or total_cards < 4:
print("Please enter a number less that 30 and more than 4")
main_menu()
else:
N = total_cards
with open("dogs.txt") as f:#opens needed file
with open("dogswrite.txt", "w") as f1:#my own file to later create a class
for i in range(N):
line=next(f).strip()#lists the input number of results each on a new line
line = line + "\n"
f1.write(line)
.next()在这里f无法使用，因为它不是列表，而是文件。您应该改用f.readline()
另外，将for循环更改为此：
for i in range(N):
line=next(f).strip() + ', '
f1.write(line)
编辑：没注意到索引行，还根据您的评论添加了逗号
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