我正在尝试创建一个循环以从Series的字典中填充字典：预期结果是：
{1: {'KEY Mult. by 10': 10, 'KEY Add by 10': 11},
2: {'KEY Mult. by 10': 20, 'KEY Add by 10': 12},
3: {'KEY Mult. by 10': 30, 'KEY Add by 10': 13},
4: {'KEY Mult. by 10': 40, 'KEY Add by 10': 14},
5: {'KEY Mult. by 10': 50, 'KEY Add by 10': 15}}
我正在做的是：
series_1 = pd.Series([1,2,3,4,5])
first_dict = dict() # creating first level of Dict
second_dict = dict({'KEY Mult. by 10': 0, # creating second level of Dict
'KEY Add by 10': 0})
for i in series_1:
first_dict[i] = second_dict
first_dict[i]['KEY Mult. by 10'] = i *10
first_dict[i]['KEY Add by 10'] = i + 10
上面的结果最终是：
{1: {'KEY Mult. by 10': 50, 'KEY Add by 10': 15},
2: {'KEY Mult. by 10': 50, 'KEY Add by 10': 15},
3: {'KEY Mult. by 10': 50, 'KEY Add by 10': 15},
4: {'KEY Mult. by 10': 50, 'KEY Add by 10': 15},
5: {'KEY Mult. by 10': 50, 'KEY Add by 10': 15}}
然后，当我尝试更改其中一个键的值时，它会为所有键更改：
first_dict[3]['KEY Mult. by 10'] = 20
print(first_dict)
{1: {'KEY Mult. by 10': 20, 'KEY Add by 10': 15},
2: {'KEY Mult. by 10': 20, 'KEY Add by 10': 15},
3: {'KEY Mult. by 10': 20, 'KEY Add by 10': 15},
4: {'KEY Mult. by 10': 20, 'KEY Add by 10': 15},
5: {'KEY Mult. by 10': 20, 'KEY Add by 10': 15}}
任何人都可以帮助我吗？
一些评论描述了解决方案，但我会详细说明一些。
字典是每个外部索引中的相同内存块。要在运行后看到这个：
for i in series_1:
first_dict[i] = second_dict
查看id()两个内部字典的，这些是内存位置：
id(first_dict[1]) # 4511987904
id(first_dict[2])
使用当前编写代码的方式，对任何字典的任何写入都将覆盖所有字典。
在您的机器上，您将有一个（一个）不同的 id 值，但这是相同的想法——它们都是相同的内存位置。
要解决此问题，您可以在for 循环中调用构造函数，它将为每个内部字典分配新内存。
for i in series_1:
first_dict[i] = dict({'KEY Mult. by 10': 0,'KEY Add by 10': 0})
first_dict[i]['KEY Mult. by 10'] = i * 10
first_dict[i]['KEY Add by 10'] = i + 10
然后您将看到id()每个内部字典的不同返回值，您可以通过以下方式确认它们是不同的内存位置id()：
>>> id(first_dict[3])
4511988352
>>> id(first_dict[1])
4511988160
同样，在您的机器上，这些将是不同id()的值，但想法是相同的，您分别为每个内部字典腾出空间。
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