是否可以在同一台计算机上运行套接字服务器和套接字客户端？

这是一个简单的可运行示例，可以帮助您入门。它开始两个线程，一个以a开头，一个ServerSocket建立Socket连接。一个连续发送字符串，另一个连续打印字符串。

您应该可以直接按原样运行此类。

import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.net.ServerSocket;
import java.net.Socket;
import java.net.UnknownHostException;

public class SocketTest {
    public static void main(String[] args) throws IOException {

        startServer();
        startSender();
    }

    public static void startSender() {
        (new Thread() {
            @Override
            public void run() {
                try {
                    Socket s = new Socket("localhost", 60010);
                    BufferedWriter out = new BufferedWriter(
                            new OutputStreamWriter(s.getOutputStream()));

                    while (true) {
                        out.write("Hello World!");
                        out.newLine();
                        out.flush();

                        Thread.sleep(200);
                    }

                } catch (UnknownHostException e) {
                    e.printStackTrace();
                } catch (IOException e) {
                    e.printStackTrace();
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }
        }).start();
    }

    public static void startServer() {
        (new Thread() {
            @Override
            public void run() {
                ServerSocket ss;
                try {
                    ss = new ServerSocket(60010);

                    Socket s = ss.accept();

                    BufferedReader in = new BufferedReader(
                            new InputStreamReader(s.getInputStream()));
                    String line = null;
                    while ((line = in.readLine()) != null) {
                        System.out.println(line);
                    }
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
        }).start();
    }
}