遍历字典时键入不匹配

Crystalsky

我偶然发现了一个我无法解决的问题。我正在尝试创建字典，例如：键：数字作为字符串项：字符串数组

当我将密钥传递给MsgBox时，一切都很好，但是当我也想添加Items时，我收到类型不匹配错误...

我的代码如下所示：

Sub test()

Dim dict As Scripting.Dictionary
Set dict = New Scripting.Dictionary

Dim records As String
Dim RecordArray() As String

Dim x As Integer
            Application.ScreenUpdating = False
            NumRows = Range("A1", Range("A1").End(xlDown)).Rows.Count
            Range("A1").Select

For x = 1 To NumRows

                If IsNumeric(Cells(x, 1).Value) Then
                    records = Trim(Cells(x, 2).Value)
                    RecordArray() = Split(records, ",")
                    dict.Add Key:=(Cells(x, 1).Value), Item:=RecordArray()

            ActiveCell.Offset(1, 0).Select

        End If
        Next x


        Application.ScreenUpdating = True

Dim key As Variant
        For Each key In dict.Keys
                MsgBox key
                MsgBox dict(key)
        Next key

End Sub

数据例如：

A1:2001 B1:  0000101,0000102,0000103
A2:2015 B2:  0000107,0000108
A3:8000 B3:  0000215,0000216,0000217

等等。请注意，B列中的值以文本之前的两个空格开头。我在这里做错了什么？我知道这段代码可能不太好，但这就像我第一次尝试使用VBA :(

帕维尔·奇兹（Pawel Czyz）

由于尝试将数组放入msgbox中，因此出现类型不匹配的情况。试试这个：

Sub test()

Dim dict As Scripting.Dictionary
Set dict = New Scripting.Dictionary
dict.CompareMode = BinaryCompare

Dim records As String
Dim RecordArray() As String

Dim x As Integer
            Application.ScreenUpdating = False
            NumRows = Range("A1", Range("A1").End(xlDown)).Rows.Count
            Range("A1").Select

For x = 1 To NumRows

                If IsNumeric(Cells(x, 1).Value) Then
                    records = Trim(Cells(x, 2).Value)
                    RecordArray() = Split(records, ",")
                    keyString = (Cells(x, 1).Value)
                    dict.Add key:=keyString, Item:=RecordArray()

            ActiveCell.Offset(1, 0).Select

        End If
        Next x


        Application.ScreenUpdating = True

Dim key As Variant
        For Each key In dict.Keys
                MsgBox key
                i = 0
                For Each Item In dict(key)
                    MsgBox (dict(key)(i))
                    i = i + 1
                Next Item
        Next key

End Sub

我提供了一个循环来显示存储在字典中的数组的每个项目。如果只需要一个msgbox，则可以使用相同的方法构建一个字符串并显示它。

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