我有输入清单
inlist = [{"id":123,"hour":5,"groups":"1"},{"id":345,"hour":3,"groups":"1;2"},{"id":65,"hour":-2,"groups":"3"}]
我需要按“组”值对字典进行分组。在那之后，我需要在新的分组列表中添加小时的最小值和最大值。输出应如下所示
outlist=[(1, [{"id":123, "hour":5, "min_group_hour":3, "max_group_hour":5}, {"id":345, "hour":3, "min_group_hour":3, "max_group_hour":5}]),
(2, [{"id":345, "hour":3, "min_group_hour":3, "max_group_hour":3}])
(3, [{"id":65, "hour":-2, "min_group_hour":-2, "max_group_hour":-2}])]
到目前为止，我设法对输入列表进行了分组
new_list = []
for domain in test:
for group in domain['groups'].split(';'):
d = dict()
d['id'] = domain['id']
d['group'] = group
d['hour'] = domain['hour']
new_list.append(d)
for k,v in itertools.groupby(new_list, key=itemgetter('group')):
print (int(k),max(list(v),key=itemgetter('hour'))
和输出是
('1', [{'group': '1', 'id': 123, 'hour': 5}])
('2', [{'group': '2', 'id': 345, 'hour': 3}])
('3', [{'group': '3', 'id': 65, 'hour': -2}])
我不知道如何按组汇总值？还有是否需要按键值对字典进行分组的更多Python方式？
首先创建一个将组号映射到字典的字典：
from collections import defaultdict
dicts_by_group = defaultdict(list)
for dic in inlist:
groups = map(int, dic['groups'].split(';'))
for group in groups:
dicts_by_group[group].append(dic)
这给了我们一个看起来像
{1: [{'id': 123, 'hour': 5, 'groups': '1'},
{'id': 345, 'hour': 3, 'groups': '1;2'}],
2: [{'id': 345, 'hour': 3, 'groups': '1;2'}],
3: [{'id': 65, 'hour': -2, 'groups': '3'}]}
然后遍历分组的字典min_group_hour并max_group_hour为每个组设置和：
outlist = []
for group in sorted(dicts_by_group.keys()):
dicts = dicts_by_group[group]
min_hour = min(dic['hour'] for dic in dicts)
max_hour = max(dic['hour'] for dic in dicts)
dicts = [{'id': dic['id'], 'hour': dic['hour'], 'min_group_hour': min_hour,
'max_group_hour': max_hour} for dic in dicts]
outlist.append((group, dicts))
结果：
[(1, [{'id': 123, 'hour': 5, 'min_group_hour': 3, 'max_group_hour': 5},
{'id': 345, 'hour': 3, 'min_group_hour': 3, 'max_group_hour': 5}]),
(2, [{'id': 345, 'hour': 3, 'min_group_hour': 3, 'max_group_hour': 3}]),
(3, [{'id': 65, 'hour': -2, 'min_group_hour': -2, 'max_group_hour': -2}])]
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