C ++复制/移动构造函数和赋值运算符

我想了解C ++复制/移动构造函数和赋值运算符，让我们首先给出代码示例：

标头：

class Person
{
public:
    Person();
    Person(const char * name, int age);
    Person(const Person &person);
    Person(Person&&) noexcept;

    virtual ~Person();

    Person &operator=(const Person & other);
    Person &operator=(Person &&other) noexcept;

    char *getName() const;
    int getAge() const;

private:
    char *name;
    int age = 0;
};

资源：

Person::Person() : age(0)
{
    this->name = new char[100];
    memset(this->name, 0, sizeof(char)*100);
}

Person::Person(const char * name, int age) : Person()
{
    std::strcpy(this->name, name);
    this->age = age;
}

Person::Person(const Person &person)
{
    if(this == &person)
    {
        return;
    }
    //delete[](name);
    this->name = new char[100];
    memset(this->name, 0, sizeof(char)*100);
    std::strcpy(name, person.name);
    age = person.age;
}

Person::Person(Person &&other) noexcept
{
    if(this == &other)
    {
        return;
    }
    //delete[](name);
    name = other.name;
    age = other.age;
    other.name = nullptr;
    other.age = 0;
}

Person &Person::operator=(const Person &other)
{
    if(this == &other)
    {
        return *this;
    }
    delete[](name);
    name = new char[100];
    memset(name, 0, sizeof(char)*100);
    std::strcpy(name, other.name);
    age = other.age;
    return *this;
}

Person &Person::operator=(Person &&other) noexcept
{
    if(this == &other)
    {
        return *this;
    }
    delete[](name);
    name = other.name;
    age = other.age;
    other.name = nullptr;
    other.age = 0;
    return *this;
}

Person::~Person() {
    delete[](name);
    name = nullptr;
}

现在的问题是：是否真的需要在copyandmove构造函数中检查是否相等this==&other？因为它是构造函数，所以不可能与其他函数相等。并且还需要在copy和move构造函数中我们delete（释放）内存吗？由于尚未分配内存，为什么需要删除它？我之所以这样说，是因为我在许多C ++教程中看到他们删除了内存并检查是否相等。

因此，如果我是对的，那么copyandmove构造函数可以这样写：

Person::Person(const Person &person) : Person()
{
    std::strcpy(name, person.name);
    age = person.age;
}
Person::Person(Person &&other) noexcept
{
    name = other.name;
    age = other.age;
    other.name = nullptr;
    other.age = 0;
}

还有，检查move分配是否相等？

Person &Person::operator=(Person &&other) noexcept

谢谢！