输入：
z = ", "
y = " "
chands = {'theboard': [('Diamonds', 'Four'), ('Clubs', 'Three'), ('Clubs', 'King'), ('Clubs', 'Two'), ('Hearts', 'Jack')]}
我的预期输出：
'Diamonds Four, Clubs Three, Clubs King, Clubs Two, Hearts Jack'
我试过了：
print chands["theboard"][0][0]+y+chands["theboard"][0][1]+z+chands["theboard"][1][0]+y+chands["theboard"][1][1]+z+chands["theboard"][2][0]+y+chands["theboard"][2][1]
有更好的打印方法吗？
IIUC，使用map+ str.join，一次y又一次z-
>>> z.join(map(y.join, chands['theboard']))
'Diamonds Four, Clubs Three, Clubs King, Clubs Two, Hearts Jack'
如果您只想加入前三个元组，则可以chands对结果进行索引和切片-
>>> z.join(map(y.join, chands['theboard'][:3]))
'Diamonds Four, Clubs Three, Clubs King'
使用列表理解的另一种方法是-
>>> z.join([y.join(x) for x in chands['theboard'][:3]])
'Diamonds Four, Clubs Three, Clubs King'
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