我有一個包含關鍵的數組counted，並placement對此我之前我想分組排序。數組應首先按 排序counted，然後對於每個重複項counted，應按 排序placement。
$array = [
[
'id' => 1,
'placement' => 8,
'counted' => 3
'user' => ['name' => 'foo'],
],
[
'id' => 2,
'placement' => 5,
'counted' => 3
'user' => ['name' => 'bar'],
],
[
'id' => 3,
'placement' => 1,
'counted' => 2
'user' => ['name' => 'foobar'],
]
];
我在這裡的預期輸出是：
$array = [
[
'id' => 2,
'placement' => 5,
'counted' => 3
'user' => ['name' => 'bar'],
],
[
'id' => 1,
'placement' => 8,
'counted' => 3
'user' => ['name' => 'foo'],
],
[
'id' => 3,
'placement' => 1,
'counted' => 2
'user' => ['name' => 'foobar'],
]
];
我試圖usort實現這一目標：
usort($array, fn($a, $b) => ((int)$a['placement'] <=> (int)$b['counted']) * -1);
但這給了我一個意想不到的結果。我嘗試的一切似乎都不起作用，任何想法將不勝感激。
因為你更喜歡使用 usort 所以這是我的答案
$array = [
[
'id' => 1,
'placement' => 8,
'counted' => 3,
'user' => ['name' => 'foo'],
],
[
'id' => 2,
'placement' => 5,
'counted' => 3,
'user' => ['name' => 'bar'],
],
[
'id' => 3,
'placement' => 1,
'counted' => 2,
'user' => ['name' => 'foobar'],
]
];
usort($array, function ($a, $b) {
if ($a['counted'] < $b['counted']) {
return 1;
}
if ($a['counted'] === $b['counted'] && $a['placement'] > $b['placement']) {
return 1;
}
});
本文收集自互联网，转载请注明来源。
如有侵权，请联系 [email protected] 删除。
我来说两句