根据文档,我做了:
var collection = new Backbone.Collection.extend({
model: ItemModel,
url: '/Items'
})
collection.fetch({ data: { page: 1} });
该网址原来是: http://localhost:1273/Items?[object%20Object]
我期待着类似的东西 http://localhost:1273/Items?page=1
那么如何在fetch方法中传递参数呢?
改变:
collection.fetch({ data: { page: 1} });
至:
collection.fetch({ data: $.param({ page: 1}) });
因此,在不做任何事情的情况下,这将与您的{data: {page:1}}
对象一起调用options
Backbone.sync = function(method, model, options) {
var type = methodMap[method];
// Default JSON-request options.
var params = _.extend({
type: type,
dataType: 'json',
processData: false
}, options);
// Ensure that we have a URL.
if (!params.url) {
params.url = getUrl(model) || urlError();
}
// Ensure that we have the appropriate request data.
if (!params.data && model && (method == 'create' || method == 'update')) {
params.contentType = 'application/json';
params.data = JSON.stringify(model.toJSON());
}
// For older servers, emulate JSON by encoding the request into an HTML-form.
if (Backbone.emulateJSON) {
params.contentType = 'application/x-www-form-urlencoded';
params.processData = true;
params.data = params.data ? {model : params.data} : {};
}
// For older servers, emulate HTTP by mimicking the HTTP method with `_method`
// And an `X-HTTP-Method-Override` header.
if (Backbone.emulateHTTP) {
if (type === 'PUT' || type === 'DELETE') {
if (Backbone.emulateJSON) params.data._method = type;
params.type = 'POST';
params.beforeSend = function(xhr) {
xhr.setRequestHeader('X-HTTP-Method-Override', type);
};
}
}
// Make the request.
return $.ajax(params);
};
因此,它将“数据”发送到jQuery.ajax,它将尽力将所有params.data
内容附加到URL。
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