目前我有一个btn,其调用函数如下:
function ingredientsList() {
const allIngredients = [].concat(...ingredientsResults.map(obj => obj.ingredients))
allIngredients.reduce((acc, item) => {
acc[item] = (acc[item] || 0) + 1
return (document.getElementById("resultsDiv").innerText = acc)
},{})
};
这将从一堆数组中获取信息,如下所示:
const ingredientsResults = [
{
dinnerName: "Vegetable Soup",
ingredients: ["potatoes", "onion", "spring onion", "lentils", "beans", "turnip" ]
},
{
dinnerName: "Spaghetti",
ingredients: ["spaghetti pasta", "tomato box","tomato box", "onion", "sundried tomatoes", "tomato paste", "lentils"]
},
{
dinnerName: "Fiskebolle",
ingredients: ["box of fiskebolle", "box of fiskebolle", "potatoes", "brocolli", "carrots"]
}
];
当单击按钮时,它会将[Object,object]返回到“ resultsDiv”。我研究了如何将其放入具有固定结果的列表/表中,但我发现的唯一是JSON.stringify(),并且给我一堆废话!是否有这个原因,或者我缺少什么?我主要想在表/列表中显示结果
我想要的结果如下:
{potatoes: 2, onion: 2, spring onion: 1, lentils: 2, beans: 1, …}
beans: 1
box of fiskebolle: 2
brocolli: 1
carrots: 1
lentils: 2
onion: 2
potatoes: 2
spaghetti pasta: 1
spring onion: 1
sundried tomatoes: 1
tomato box: 2
tomato paste: 1
turnip: 1
任何帮助是极大的赞赏!
您可以做的是在创建带有成分名称和数量的对象之后,创建一个遍历所有对象的新循环,并创建tr
和td
const ingredientsResults = [
{
dinnerName: "Vegetable Soup",
ingredients: ["potatoes", "onion", "spring onion", "lentils", "beans", "turnip" ]
},
{
dinnerName: "Spaghetti",
ingredients: ["spaghetti pasta", "tomato box","tomato box", "onion", "sundried tomatoes", "tomato paste", "lentils"]
},
{
dinnerName: "Fiskebolle",
ingredients: ["box of fiskebolle", "box of fiskebolle", "potatoes", "brocolli", "carrots"]
}
];
function ingredientsList() {
const allIngredients = [].concat(...ingredientsResults.map(obj => obj.ingredients))
const result = allIngredients.reduce((acc, item) => {
acc[item] = (acc[item] || 0) + 1
return acc // change this
},{})
// add this
const table = document.querySelector('#myTable')
Object.keys(result).forEach(dname => {
const tr = document.createElement('tr')
const td1 = document.createElement('td')
const td2 = document.createElement('td')
td1.innerText = dname
td2.innerText = result[dname]
tr.append(td1)
tr.append(td2)
table.append(tr)
})
// end
};
ingredientsList()
<table id="myTable">
</table>
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