val time
5.6 2021-11-18 03:00:00
2.034 2021-11-18 05:00:00
1.171 2021-11-18 07:00:00
3.023 2021-11-18 09:00:00
4.202 2021-11-18 16:00:00
1.202 2021-11-18 17:00:00
5.202 2021-11-18 18:00:00
7.202 2021-11-18 19:00:00
2.202 2021-11-18 20:00:00
12.202 2021-11-18 21:00:00
1.202 2021-11-18 21:00:00
上面是我的數據框,我想繪製它(x=time,y=value),並將值繪製為紅色(val>5)。
plt.plot(ab['time'], ab['value'], '-gD', markevery=marks, label='line with select markers')
其中標記[7.202,12.202]
是我手動創建的列表。但這不起作用。error -: markevery is iterable but not a valid numpy fancy index
如果條件為真,則使用不同標記的線圖 python 3我在這裡找到了一個,但是如果點很多,這很耗時
pandas.DataFrame.plot
%M-%d %H
自動格式化。當有更多數據時,格式會發生變化,還有其他答案討論如何格式化熊貓日期時間軸。import pandas as pd
import matplotlib.pyplot as plt
# sample data
data = {'val': [5.6, 2.034, 1.171, 3.023, 4.202, 1.202, 5.202, 7.202, 2.202, 12.202, 1.202], 'time': ['2021-11-18 03:00:00', '2021-11-18 05:00:00', '2021-11-18 07:00:00', '2021-11-18 09:00:00', '2021-11-18 16:00:00', '2021-11-18 17:00:00', '2021-11-18 18:00:00', '2021-11-18 19:00:00', '2021-11-18 20:00:00', '2021-11-18 21:00:00', '2021-11-18 21:00:00']}
df = pd.DataFrame(data)
# convert the time column to a datetime dtype
df.time = pd.to_datetime(df.time)
# get the values greater than 5
masked = df[df.val.gt(5)]
# plot the line plot
ax = df.plot(x='time', marker='o', figsize=(15, 5), zorder=0)
# plot those greater than 5
masked.plot(kind='scatter', x='time', y='val', color='red', ax=ax, s=30, label='outliers')
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