我有一个数组
Array
(
[0] => stdClass Object
(
[tab_option_name_selector] => 2
[fieldtype] => notes
[order] => 12
)
[1] => stdClass Object
(
[tab_option_name_selector] => 2
[fieldtype] => notes
[order] => 8
)
[2] => stdClass Object
(
[tab_option_name_selector] => 1
[order] => 2
[fieldtype] => selectbox
)
[3] => stdClass Object
(
[tab_option_name_selector] => 2
[order] => 3
[fieldtype] => selectbox
)
)
我正在尝试使此usort函数正常工作
function osort(&$array, $props)
{
if(!is_array($props))
$props = array($props => true);
$me = usort($array, function($a, $b) use ($props) {
foreach($props as $prop => $ascending)
{
if($a->$prop != $b->$prop)
{
if($ascending)
return $a->$prop > $b->$prop ? 1 : -1;
else
return $b->$prop > $a->$prop ? 1 : -1;
}
}
return -1; //if all props equal
});
print_r($props);
return ($me);
}
$tab = osort($objectArray, "tab_option_name_selector", "order");
因此按标签排序然后排序。
$ tab为空-有什么想法我做错了吗？
为什么要增加间接级别并使事情变得更加混乱？为什么不直接usort($objectArray, "sortObjects");使用sortObjects($a,$b)函数执行比较器所进行的操作：根据输入返回负数/ 0 /正数？
如果选项卡不同，则返回它们的比较；如果相同，则返回订单比较；完成。
$array = array(
(object)array(
'tab_option_name_selector' => 2,
'fieldtype' => 'notes',
'order' => 12
),
(object)array(
'tab_option_name_selector' => 2,
'fieldtype' => 'notes',
'order' => 8
),
(object)array(
'tab_option_name_selector' => 1,
'order' => 2,
'fieldtype' => 'selectbox'
),
(object)array(
'tab_option_name_selector' => 2,
'order' => 3,
'fieldtype' => 'selectbox'
)
);
function compareTabAndOrder($a, $b) {
// compare the tab option value
$diff = $a->tab_option_name_selector - $b->tab_option_name_selector;
// and return it. Unless it's zero, then compare order, instead.
return ($diff !== 0) ? $diff : $a->order - $b->order;
}
usort($array, "compareTabAndOrder");
print_r($array);
本文收集自互联网，转载请注明来源。
如有侵权，请联系 [email protected] 删除。
我来说两句