我有两个这样的结果集：
// Result 1
[
{ value: "0", display: "Jamsheer" },
{ value: "1", display: "Muhammed" },
{ value: "2", display: "Ravi" },
{ value: "3", display: "Ajmal" },
{ value: "4", display: "Ryan" }
]
// Result 2
[
{ value: "0", display: "Jamsheer" },
{ value: "1", display: "Muhammed" },
{ value: "2", display: "Ravi" },
{ value: "3", display: "Ajmal" },
]
我需要的最终结果是这些数组之间的差异–最终结果应如下所示：
[{ value: "4", display: "Ryan" }]
是否可以在JavaScript中执行类似的操作？
仅使用本机JS，类似的方法将起作用：
a = [{ value:"4a55eff3-1e0d-4a81-9105-3ddd7521d642", display:"Jamsheer"}, { value:"644838b3-604d-4899-8b78-09e4799f586f", display:"Muhammed"}, { value:"b6ee537a-375c-45bd-b9d4-4dd84a75041d", display:"Ravi"}, { value:"e97339e1-939d-47ab-974c-1b68c9cfb536", display:"Ajmal"}, { value:"a63a6f77-c637-454e-abf2-dfb9b543af6c", display:"Ryan"}]
b = [{ value:"4a55eff3-1e0d-4a81-9105-3ddd7521d642", display:"Jamsheer", $$hashKey:"008"}, { value:"644838b3-604d-4899-8b78-09e4799f586f", display:"Muhammed", $$hashKey:"009"}, { value:"b6ee537a-375c-45bd-b9d4-4dd84a75041d", display:"Ravi", $$hashKey:"00A"}, { value:"e97339e1-939d-47ab-974c-1b68c9cfb536", display:"Ajmal", $$hashKey:"00B"}]
function comparer(otherArray){
return function(current){
return otherArray.filter(function(other){
return other.value == current.value && other.display == current.display
}).length == 0;
}
}
var onlyInA = a.filter(comparer(b));
var onlyInB = b.filter(comparer(a));
result = onlyInA.concat(onlyInB);
console.log(result);本文收集自互联网，转载请注明来源。
如有侵权，请联系 [email protected] 删除。
我来说两句