如何使用JavaScript将对象数组的重复元素合并为一个

巴拉斯·库玛·穆鲁根

我对javascript不熟悉，也不知道如何搜索此问题。在这里，我已经简要说明了我的问题。以下是我必须从中找出数据中相似条目并将它们组合为一个对象的数据。这是我的数据：

var myArr = [{
        "Company": "Samsung",
        "model": "Galaxy S2",
        "screen_size": "5.5"
    },
    {
        "Company": "Samsung",
        "model": "Galaxy S3",
        "screen_size": "5.5"
    },
    {
        "Company": "Samsung",
        "model": "Galaxy S4",
        "screen_size": "5.5"
    },
    {
        "Company": "Xiaomi",
        "model": "Redmi 2",
        "screen_size": "4.7"
    },
    {
        "Company": "Xiaomi",
        "model": "Redmi 4",
        "screen_size": "5"
    },
    {
        "Company": "Xiaomi",
        "model": "Redmi Note 4",
        "screen_size": "5.5"
    }
]

我想合并数组中所有重复项。因此，我的数据结果应如下所示：

[{
    "Company": "Samsung",
    "models": [{
        "Galaxy S2": {
            "screen_size": "5.5"
        }
    }, {
        "Galaxy S3": {
            "screen_size": "5.6"
        }
    }, {
        "Galaxy S4": {
            "screen_size": "5.7"
        }
    }]
}, {
    "Company": "Xiaomi",
    "models": [{
        "Redmi 2": {
            "screen_size": "4.7"
        }
    }, {
        "Redmi 4": {
            "screen_size": "5"
        }
    }, {
        "Redmi Note 4": {
            "screen_size": "5.5"
        }
    }]
}]

有人请帮帮我。

哈桑·伊玛目（Hassan Imam）

您可以在对象array#reduce的Company键上使用对对象进行分组，并使用提取所有值Object.values()。

var myArr=[{ "Company": "Samsung", "model": "Galaxy S2", "screen_size": "5.5" }, { "Company": "Samsung", "model": "Galaxy S3", "screen_size": "5.5" }, { "Company": "Samsung", "model": "Galaxy S4", "screen_size": "5.5" }, { "Company": "Xiaomi", "model":"Redmi 2", "screen_size": "4.7" }, { "Company": "Xiaomi", "model": "Redmi 4", "screen_size": "5" }, { "Company": "Xiaomi", "model": "Redmi Note 4", "screen_size": "5.5" } ],
    result = Object.values(myArr.reduce((r,o) => {
      r[o.Company] = r[o.Company] || {'Company': o.Company, 'Models' : []};
      r[o.Company]['Models'].push({[o.model]:{'screen_size' : o.screen_size}});
      return r;
    }, {}));

console.log(result);

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