我有以下两个列表：
advanced_filtered_list_val1 = [row for row in cleaned_list if float(row[val1]) < wert1]
advanced_filtered_list_val2 = [row for row in cleaned_list if float(row[val2]) < wert2]
如何使用选项and和/或or将映射的列表映射到列表中？
列表中的数据是字典，我搜索和过滤列表中的某些行。我想过滤两个值。这很好。但是，现在如何将其映射到列表中进行过滤？
我尝试了以下操作：
select = int(input())
#and operation
if select == 1:
mapped_list = [row for row in advanced_filtered_list_val1 and advanced_filtered_list_val2]
for x in mapped_list:
print(x)
#or operation
if select == 2:
mapped_list = [row for row in advanced_filtered_list_val1 or advanced_filtered_list_val2]
for x in mapped_list:
print(x)
我按如下所示导入数据：
faelle = [{k: v for k, v in row.items()}
for row in csv.DictReader(csvfile, delimiter=";")]
我现在要从wert1和wert2和wert1或过滤wert2。那意味着在and子句上它应该在两个过滤器上true，在or子句上它应该是wert1或之一wert2 True
您要过滤包含cleaned_list两个wert类似条件（AND）或其中至少一个（OR）的字典。你能做的是
import operator as op
ineq_1 = 'gt'
ineq_2 = 'lt'
select = 2
andor = {
1:lambda L: filter(
lambda d: getattr(op,ineq_1)(float(d[val1]), wert1)
and getattr(op,ineq_2)(float(d[val2]), wert2),
L
),
2:lambda L: filter(
lambda d: getattr(op,ineq_1)(float(d[val1]), wert1)
or getattr(op,ineq_2)(float(d[val2]), wert2),
L
),
}
mapped_list = andor[select](cleaned_list)
for x in mapped_list:
print(dict(x))
可能的选择是gt（大于），lt（小于）或eq。
and_ 和 or_ ， 甚至可以使事情更加“动态” operator 。例如，
#Where the two following ix2-like stuffs are defined to make
# a correspondence between names one knows, and methods of the
# module operator.
ix2conj = {
1:'and_',
2:'or_',
}
ix2ineq = {
'<' :'lt',
'==':'eq',
'>' :'gt',
}
def my_filter(conjunction, inequality1, inequality2, my_cleaned_list):
return filter(
lambda d: getattr(op, ix2conj[conjunction])(
getattr(op, ix2ineq[inequality1])(float(d[val1]), wert1),
getattr(op, ix2ineq[inequality2])(float(d[val2]), wert2)
),
my_cleaned_list
)
ineq_1 = '>'
ineq_2 = '<'
select = 2
print(my_filter(select, ineq_1, ineq_2, cleaned_list))
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