我只想将文件从一个文件夹移动到另一个文件夹(已经知道该怎么做),并且在此过程中检查目标文件夹中的所有文件并删除具有相同名称的文件。
我有两个文件夹/ src和/ dst。
在文件夹/ src中,我有:
- 'access.log.1.txt'
并在文件夹/ dst中:
- 'access.log.1.20171110_115840565311.txt'
- 'access.log.1.20171110_115940565311.txt'
- 'access.log.2.20171110_115940565311.txt'
当我将/ src中的文件移动到/ dst时,我想删除/ src中名为该文件的所有文件,但不包括/ dst文件中的datetime()扩展名。
因此,执行后/ dst文件夹应如下所示:
- 'access.log.1.txt'
- 'access.log.2.20171110_115940565311.txt'
这是我必须将文件从/ src移至/ dst的代码:
entrada = ENTRADA #This 3 are the paths to the folders /src
salida = SALIDA # /dst
error=ERROR # /err
files=glob.glob(entrada)
for file in files:
fichero=open(file,encoding='utf-8')
try:
for line in fichero:
la=line.replace("-","")
li=la.replace('”'+chr(10),'')
li=li.split('"')
line_DB(li)
fichero.close()
if TIME_RENAME=='True':
execution=str(datetime.now())
execution=execution.replace('.','')
execution=execution.replace('-','')
execution=execution.replace(' ','_')
execution_time=execution.replace(':','')
base = os.path.splitext(file)[0]
base=base+'.'+execution_time+'.txt'
os.rename(file,base)
file=base
else:
print('Hello')
#This is where I need the code
shutil.move(file, salida)
con.commit()
except:
logging.error(sys.exc_info())
print(sys.exc_info())
fichero.close()
shutil.move(file, error)
有人可以帮助我吗?
谢谢!!
桑迪普(Sandip)的答案应该有效,但是如果您特别希望按照问题中的说明进行操作,则可以这样做:
import os
src_filename = "access.log.1.txt"
dst_dir = "test"
for filename in os.listdir(dst_dir):
# Filter files based on number of . in filename
if filename.count(".") < 4:
continue
# We need to remove the datetime extension before comparing with our filename
filename_tokens = filename.split(".") # List of words separated by . in the filename
print "Tokens:", filename_tokens
# Keep only indexes 0, 1, 2 and 4 (exclude index 3, which is the datetime-string)
datetime_string = filename_tokens.pop(3) # pop() also removes the datetime-string
print "Datetime:", datetime_string
dst_filename = ".".join(filename_tokens)
print "Destination filename:", dst_filename
# Check if the destination filename now matches our source filename
if dst_filename == src_filename:
# Get full path of file to be deleted
filepath = os.path.join(dst_dir, filename)
# Delete it
print "Deleting:", filepath
os.remove(filepath)
print "----------------------"
请注意,此方法假设所有目标文件名看起来都与问题中的文件名相同,即,所有目标文件名均具有4个句点(.
),并且datetime字符串始终位于第三个和第四个句点之间。
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