我有 DOM
<div class="" data-zone-data="{"id":"97017425"}"data-zone-name="category-link">
<div class="_35SYu _1vnug" data-tid="acbe4a11 f8542ee1">
<a href="/catalog--kompiuternaia-tekhnika/54425" class="_3Lwc_">
<span class="_3z8Gf">Компьютеры</span>
</a>
</div>
</div>
enter code here
构造函数:
public YandexBeforeSearch(WebDriver driver, String search){
this.driver = driver;
this.driver.get("https://yandex.ru/search?text=" + search);
}
我的方法:
public void clickToSite(){
LinkYandexMarket = driver.findElement(By.xpath("//a[@accesskey='1']"));
LinkYandexMarket.click();
}
public void clickTYandexPC(){
LinkYandexPC = driver.findElement(By.xpath("//a[@href='/catalog--kompiuternaia-tekhnika/54425']"));
LinkYandexPC.click();
}
我的测试:
@Test
public void testOpen(){
YandexBeforeSearch yandexBeforeSearch = new YandexBeforeSearch(chromeDriver, "yandex market");
yandexBeforeSearch.clickToSite();
yandexBeforeSearch.clickTYandexPC();
}
例外:
org.openqa.selenium.NoSuchElementException: no such element: Unable to locate element: {"method":"xpath","selector":"//a[@href='catalog--kompiuternaia-tekhnika/54425']"}
我还使用了其他属性。该问题仅发生在此站点上。我无法点击该类别的链接。
//a[@accesskey='1']
单击第一个链接时会打开一个新窗口。
我们需要切换到那个新窗口来点击 //a[@href='/catalog--kompiuternaia-tekhnika/54425']
// Click on the 1st link.
driver.findElement(By.xpath("//a[@accesskey='1']")).click();
// Get parent window.
String parentwindow = driver.getWindowHandle();
// Get all window handles.
Set<String> windows = driver.getWindowHandles();
List<String> windows1 = new ArrayList<>(windows);
// Switch to the new window to click on the other link.
driver.switchTo().window(windows1.get(1));
driver.findElement(By.xpath("//a[@href='/catalog--kompiuternaia-tekhnika/54425']")).click();
// Switch back to parent window, if required.
driver.switchTo().window(parentwindow);
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我来说两句