我有一个值列表
lst = [75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 118, 119, 120, 121, 122, 123, 124, 125, 126, 127, 155, 156, 157, 158, 159, 160, 161, 162, 163, 164, 185, 186, 187, 188, 189, 190, 191, 192, 193, 195, 196, 197, 198, 199, 221, 222, 223, 224, 225, 226, 273, 274, 275, 276, 277, 278, 279, 280, 281, 282, 283, 309, 310, 311, 312, 313, 314, 315, 316, 371, 372, 373, 374, 375, 376, 377, 378, 379, 380, 401, 402, 403, 404, 405, 406, 407, 408, 439, 440]
如果您仔细查看列表,您会看到值在增加,然后有一个很大的跳跃,然后值再次开始增加。
我怎么能分开所以最后我可以拥有
[[75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88], [118, 119, 120, 121, 122, 123, 124, 125, 126, 127], [155, 156, 157, 158, 159, 160, 161, 162, 163, 164]...[439, 440]]
这是一个解决方案itertools
。我用作保持连续数字的条件(感谢@KarlKnechtel)。
from itertools import groupby
diff = [item - i for i, item in enumerate(lst)]
[[x[1] for x in g] for i,g in groupby((zip(diff,lst)), lambda x: x[0])]
输出:
[[75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88],
[118, 119, 120, 121, 122, 123, 124, 125, 126, 127],
[155, 156, 157, 158, 159, 160, 161, 162, 163, 164],
[185, 186, 187, 188, 189, 190, 191, 192, 193],
[195, 196, 197, 198, 199],
[221, 222, 223, 224, 225, 226],
[273, 274, 275, 276, 277, 278, 279, 280, 281, 282, 283],
[309, 310, 311, 312, 313, 314, 315, 316],
[371, 372, 373, 374, 375, 376, 377, 378, 379, 380],
[401, 402, 403, 404, 405, 406, 407, 408],
[439, 440]]
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