我正在尝试遍历位于相对路径中的所有 .txt 文件名。（在我的 Mac 上，即使 .py 文件与 .txt 文件位于同一目录中，我也无法在没有相对路径的情况下使其工作）我使用了以下内容：
import os
path_str = "Chapter 10_Files_Exceptions/*.txt"
当我遍历名为 filenames 的列表中的每个文件名时......
filenames = ['Chapter 10_Files_Exceptions/alice.txt', 'Chapter 10_Files_Exceptions/siddhartha.txt',
'Chapter 10_Files_Exceptions/moby_dick.txt', 'Chapter 10_Files_Exceptions/little_women.txt'
]
for filename in filenames:
count_words(filename)
我得到这个结果...
*.txt has 29465 within it.
*.txt has 42172 within it.
*.txt has 215830 within it.
*.txt has 189079 within it.
*如何执行此操作并显示每个文件名而不是.txt？
import os
path_str = "Chapter 10_Files_Exceptions/*.txt"
def count_words(filename):
"""Count the approximate number of words in a file."""
try:
with open(filename, encoding='utf-8') as f:
contents = f.read()
except FileNotFoundError:
print(f"{os.path.basename(path_str).capitalize()} is not located in your current working directory.")
else:
words = contents.split()
num_words = len(words)
print(f"{os.path.basename(path_str).capitalize()} has {num_words} within it.")
filenames = ['Chapter 10_Files_Exceptions/alice.txt', 'Chapter 10_Files_Exceptions/siddhartha.txt',
'Chapter 10_Files_Exceptions/moby_dick.txt', 'Chapter 10_Files_Exceptions/little_women.txt'
]
for filename in filenames:
count_words(filename)
用于Path(filename).name从文件名中去除路径。请参阅路径库。
from pathlib import Path
def count_words(filename):
name = Path(filename).name.capitalize()
...
else:
words = contents.split()
num_words = len(words)
print(f"{name} has {num_words} within it.")
输出：
Alice.txt has 29465 within it.
Siddhartha.txt has 42172 within it.
Moby_dick.txt has 215830 within it.
Little_women.txt has 189079 within it.
如果您想要不带 .txt 扩展名的基本名称，请使用 Path.stem(); 例如路径/Alice.txt => Alice。
name = Path(filename).stem.capitalize()
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