使用MapStruct的嵌套列表映射

Sai A 发表于 Dev

328

你知道一个

在以下情况下，如何使用MapStruct进行bean映射。

class Source {
private String sourceId;
private List<Course> courses;  //always returns only one course
}

class Course {
private String courseName;
private List<Student> students; 
}

class Student {
private String studentName;
}

class Target {
private String targetId;
private String subjectName;
private List<Member> members;
}

class Member {
private String memberName;
}

现在，我想将sourceId映射到targetId，将courseName映射到subjectName，将StudentName映射到memberName（从列表到列表）。

菲利普

首先，Source总是包含一个过程，为什么不将其Course设为元素而不是List？

如果这样做，映射将更加简单。在您当前的设置下，它要复杂一些。

@Mapper
public interface MyMapper {

    @Mapping(target = "targetId", source = "sourceId")
    @Mapping(target = "subjectName", source = "courses")
    @Mapping(target = "members", source = "courses")
    Target map(Source source);

    default String subjectName(List<Course> courses) {
        if (courses == null || courses.isEmpty()) {
            return null;
        }
        return courses.get(0).getCourseName();
    }

    default List<Member> toMembersFromCourses(List<Course> courses) {
        if (courses == null || courses.isEmpty()) {
            return null;
        }
        return toMembers(courses.get(0).getStudents());
    }

    List<Member> toMembers(List<Student> students);

    @Mapping(target = "memberName", source = "studentName")
    Member toMember(Student student);
}

如果Course不是列表。那么您可以使用1.2.0.Final做得更优雅。

@Mapper
public interface MyMapper {

    @Mapping(target = "targetId", source = "sourceId")
    @Mapping(target = "subjectName", source = "course.courseName")
    @Mapping(target = "members", source = "course.students")
    Target map(Source source);

    @Mapping(target = "memberName", source = "studentName")
    Member toMember(Student student);
}

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