删除对象数组中的重复项

Venox 发表于 Dev

毒液

这部分负责处理 val 数组中的数据，因此 i 一切都是整数并将其保存在输出数组中。（val 数组有时包含浮点数，我无法使用它们）

假设下一个被处理的元素有 ax 和 y 对，它们已经在输出数组中，并且带有任何其他颜色。如何用新对象替换旧对象。

    val.forEach(element => {

        output.push({
            x: Math.round(element.x / element.width),
            y: Math.round(element.y / element.height),
            color: mapColorToBlock(element.color)

        })
    });



/* val array...
[
{"x":0,"y":0,"color":"blue","width":256,"height":256},
{"x":0,"y":256,"color":"blue","width":256,"height":256},
{"x":256,"y":256,"color":"blue","width":256,"height":256},
{"x":256,"y":0,"color":"blue","width":256,"height":256},
{"x":0,"y":256,"color":"lime","width":256,"height":256}
]
*/

/*output array after the processing(notice how there are 2 objects with x = 0 and y = 1 (the second and last entry in output))
[
  { x: 0, y: 0, color: 12 },
  { x: 0, y: 1, color: 12 },
  { x: 1, y: 1, color: 12 },
  { x: 1, y: 0, color: 12 },
  { x: 0, y: 1, color: 6 }
]
*/

新对象替换旧对象很重要。（新条目不必与旧对象在数组中的位置相同）在这种情况下，输出数组将如下所示。

[
  { x: 0, y: 0, color: 12 },
  { x: 1, y: 1, color: 12 },
  { x: 1, y: 0, color: 12 },
  { x: 0, y: 1, color: 6 }
]

鲍尔

Shuvo 答案的修改版本。

只有当 mapColorToBlock 可以在对传递的相同值的连续调用中返回不同的结果时，这个才有意义，否则 Shuvo 跳过重复项的答案会更好。

“重要的是，新对象替换旧对象”...

let val = [
{"x":0,"y":0,"color":"blue","width":256,"height":256},
{"x":0,"y":256,"color":"blue","width":256,"height":256},
{"x":256,"y":256,"color":"blue","width":256,"height":256},
{"x":256,"y":0,"color":"blue","width":256,"height":256},
{"x":0,"y":256,"color":"lime","width":256,"height":256}
];

let output = [];

val.forEach(element => {
  const x = Math.round(element.x / element.width);
  const y = Math.round(element.y / element.height);
  const found = output.find(item => item.x === x && item.y === y);
  
  if (found) {
    found.color = mapColorToBlock(element.color);
  } else {  
    output.push({
        x: x,
        y: y,
        color: mapColorToBlock(element.color)
    })
  }
});

本文收集自互联网，转载请注明来源。

如有侵权，请联系 [email protected] 删除。