我正在制作一个词汇测试程序，我需要让每个条目输入答案。但是，我发现制作每个条目的效率非常低，所以我曾经for i in range(0,35)制作过条目。但现在我坚持获取每个条目的价值。如何制作一个按钮来收集.get()每个没有名称的条目？
import tkinter
from tkinter import *
window = tkinter.Tk()
container = tkinter.Frame(window)
canvas = tkinter.Canvas(container)
window.title('Rescue word test')
window.geometry('640x480')
window.resizable(True, True)
scrollbar = tkinter.Scrollbar(container, orient="vertical", command=canvas.yview)
#scroll
main_frame = Frame(window)
main_frame.pack(fill=BOTH, expand=1)
my_canvas = Canvas(main_frame)
my_canvas.pack(side=LEFT, fill=BOTH, expand=1)
my_scrollbar = tkinter.Scrollbar(main_frame, orient=VERTICAL, command=my_canvas.yview)
my_scrollbar.pack(side=RIGHT, fill=Y)
my_canvas.configure(yscrollcommand=my_scrollbar.set)
my_scrollbar.bind('<Configure>', lambda e: my_canvas.configure(scrollregion= my_canvas.bbox("all")))
second_frame = Frame(my_canvas)
my_canvas.create_window((0,0), window= second_frame, anchor="nw")
def mouse_scroll(event):
my_canvas.yview_scroll(-1 * int((event.delta / 120)), "units")
my_canvas.bind_all("<MouseWheel>", mouse_scroll)
def getEntry( i ):
return list( second_frame.children.values() )[ i ]
Day21_eng = ['exquisite', 'acquisition', 'regulate', 'transportation', 'insight', 'straightforward', 'cultivate', 'innovation', 'preserve', 'odor', 'exception', 'munch', 'proclaim', 'slap', 'variability', 'investigate', 'flare', 'outpace', 'genuine', 'plead', 'fossilize', 'toil', 'drastic', 'withhold', 'inanimate', 'clockwise', 'amnesia', 'revive', 'theorize', 'culprit', 'limp', 'worn-out', 'indignity', 'span', 'bribe']
Day21_kor = [['우아한', '정교한', '절묘한'], ['취득', '획득', '습득'], ['규제하다', '통제하다'], ['운송', '운임', '추방'], ['통찰', '통찰력'], ['명확한', '솔직한'], ['경작하다', '기르다', '장려하다', '육성하다'], ['혁신'], ['보전', '보호지', '보호하다', '보존하다'], ['냄새', '악취', '기미', '낌새'], ['예외'], ['우적우적 먹다'], ['선언하다'], ['찰싹 때리다'], ['변화성', '가변성', '변용성'], ['조사하다'], ['불끈 성나게 하다', '이글거리다', '불꽃', '타오름'], ['앞지르다', '속도가 더 빠르다'], ['진짜의', '진품의'], ['탄원하다', '변호하다', '애원하다'], ['고착화하다', '화석화하다'], ['수고', '노고', '힘들게 일하다'], ['급격한', '극단적인'], ['보류하다', '유보하다'], ['생명 없는', '무생물의'], ['시계방향으로'], ['기억상실'], ['부활시키다', '되살아나게 하다'], ['이론화하다'], ['죄인', '범죄자', '장본인'], ['절뚝거리다', '느릿느릿 가다', '기운이 없는','축 처진'], ['닳아빠진', '진부한', '지친'], ['모욕', '무례', '치욕'], ['기간', '폭', '범위', '걸치다', '이르다'], ['뇌물을 주다', '뇌물']]
b = 0
for i in range(0,35):
lable = Label(second_frame, text= Day21_eng[b])
lable.grid(column=0, row=b)
#입력 값 35개
entry = tkinter.Entry(second_frame, width=30)
entry.grid(row=b, column=1, sticky='nsew')
# important to bind each one for access
entry.bind('<Return>', getEntry)
b += 1
b_check = Button(second_frame, text='grade')
b_check.grid(columnspan=2, row=36)
window.mainloop()
如果我按下“等级”按钮，我想发送一个命令来检查.get()每个条目的 是否in是Day21_kor列表。
您可以使用 alist来存储Entry小部件并list在grade.
...
def check():
for i, e in enumerate(entries):
value = e.get()
print(value, value in Day21_kor[i])
# or whatever you want to do
entries = []
for row, item in enumerate(Day21_eng):
lable = tkinter.Label(second_frame, text=item)
lable.grid(column=0, row=row)
#입력 값 35개
entry = tkinter.Entry(second_frame, width=30)
entry.grid(row=row, column=1, sticky='nsew')
# important to bind each one for access
entry.bind('<Return>', getEntry)
entries.append(entry) # save 'entry' into list
b_check = tkinter.Button(second_frame, text='grade', command=check)
b_check.grid(columnspan=2, row=36)
请注意，您的代码中还有其他问题：
container，canvas和scrollbar<Configure>的second_frame，而不是my_scrollbargetEntry()执行时异常。你实际上想在这个函数中做什么？本文收集自互联网，转载请注明来源。
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