我需要将以下 JArray 转换为对象。我的问题是,我需要用属性来做到这一点。因为我无法在解耦类中更改以下调用:
var message = JsonConvert.DeserializeObject(e.Message, messageType)
JSON
[71,[[77372266,1508067366000,-0.12144759,5517.4],[77372265,1508067366000,-0.020001,5518.2],[77372251,1508067362000,-0.01,5517.2],[77372235,1508067358000,0.020001,5517.8],[77372220,1508067352000,-0.41883579,5517.3],[77372218,1508067352000,-1.05740887,5517.2],[77372211,1508067351000,-1.8084,5517.2],[77372207,1508067350000,-0.01565918,5517.2],[77372206,1508067349000,-0.01721768,5514.3],[77372205,1508067349000,-0.10347625,5514.3],[77372201,1508067348000,-1.08183286,5513.1],[77372200,1508067348000,-0.04218858,5513.1],[77372199,1508067348000,-0.020001,5513.3],[77372198,1508067348000,-0.020001,5513.3],[77372197,1508067348000,-0.020001,5513.3],[77372196,1508067348000,-0.020001,5513.3],[77372195,1508067348000,-2.16396207,5513.3],[77372194,1508067348000,-1.5601,5513.5],[77372193,1508067348000,-0.13520397,5514.2],[77372192,1508067347000,-0.01479603,5514.2],[77372191,1508067347000,-0.13659854,5513.4],[77372189,1508067346000,-0.01597635,5513.3],[77372187,1508067346000,-0.19812221,5513.3],[77372184,1508067346000,-0.01261482,5513.3],[77372183,1508067346000,0.131033,5519.7],[77372182,1508067346000,0.2011,5519.4],[77372181,1508067346000,0.074337,5518.2],[77372180,1508067346000,0.125,5517.5],[77372179,1508067346000,0.06401,5516.5],[77372178,1508067346000,0.05305,5516.3]]]
我的课程
public class Root
{
public int ChannelId { get; set; }
public List<Item> Data { get; set; }
}
public class Item
{
public int Id { get; set; }
public long Timestamp { get; set; }
public decimal Price { get; set; }
public decimal Size { get; set; }
}
如果您使用Newtonsoft JSON 库(现在称为 JSON.NET),您可以使用Jsonconverter
该类来创建您自己的自定义转换器。
你的班级看起来像:
public class MyCustomConverter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
return typeof(Root).GetTypeInfo().IsAssignableFrom(objectType.GetTypeInfo());
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
if (reader.TokenType == JsonToken.StartArray)
{
JArray rootToken = JArray.Load(reader);
if (rootToken[0] != null && rootToken[1] != null)
{
var root = new Root(rootToken[0].Value<int>(), this.readItems(rootToken[1]));
return root;
}
}
return existingValue;
}
private IList<Item> readItems(JToken items)
{
var itemList = new List<Item>();
if (items.Type == JTokenType.Array)
{
foreach(var item in items.Children())
{
if (item.Type == JTokenType.Array && item.Count() == 4)
{
itemList.Add(new Item(
item[0].Value<int>(),
item[1].Value<long>(),
item[2].Value<decimal>(),
item[3].Value<decimal>()));
}
}
}
return itemList;
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
throw new NotImplementedException();
}
}
请注意,当前状态下的此自定义转换器只能将 JSON 转换为对象,如果您希望它能够将Root
对象转换为 JSON 字符串,则需要自己实现该WriteJson
方法。
你说由于解耦依赖,你不能改变被调用者调用反序列化方法的方式。您可以做的是覆盖JSONConvert.DefaultSettings属性并明确告诉它使用自定义转换器。
JsonConvert.DefaultSettings = (() =>
{
var settings = new JsonSerializerSettings();
settings.Converters.Add(new MyCustomConverter());
return settings;
});
var jsonString = "...";
var root = JsonConvert.DeserializeObject(jsonString, typeof(Root));
本文收集自互联网,转载请注明来源。
如有侵权,请联系 [email protected] 删除。
我来说两句