有没有办法通过迭代创建变量？

所以我试图为在线二十一点程序编写代码，但我在编程时遇到了麻烦，因为我需要使用从列表中随机抽取的最多 11 个变量进行计算。现在，我对该部分的代码是：

while user_card_total_one <= 21:
    user_move = input("Would you like to stand or hit? ")
    user_move = user_move.lower()
    if user_move == "stand":
        break
    elif user_move == "hit":
        user_card_three = random.choice(deck)
        deck.remove(user_card_three)
        a_or_an_one = " a "
        if user_card_three == 8 or user_card_three == "Ace":
            a_or_an_one = " an "
        print("You were dealt" + a_or_an_one + str(user_card_three) + ".")
        if type(user_card_three) == str and user_card_one != "Ace":
            user_card_one = 10
        if user_card_three == "Ace":
            user_card_total_one = user_card_total_one + 1
            user_card_total_two = user_card_total_two + 11
            if user_card_total_two > 21:
                print("Your card total is " + str(user_card_total_one) + ".")
            else:
                print("Your card total is " + str(user_card_total_one) + " or " + str(user_card_total_two) + ".")
        else:
            user_card_total_one = user_card_total_one + user_card_three
            user_card_total_two = user_card_total_two + user_card_three
            print("Your card total is " + str(user_card_total_one) + ".")
        if user_card_total_one > 21:
            print("Unfortunately, you busted and lost.")
            print("The dealer has collected your bet.")
            bust = True
            break
    else:
        print("Sorry, thats not a valid input, please try again.")

现在，我可以多次编写此代码，以便考虑用户决定执行的操作，但代码中唯一的更改将是变量名称。我想知道是否有某种方法可以使这个for循环成为变量name依赖于 i的循环？我尝试使用字典：

card = {
    1: "Ace",
    2: "King",
    3: 2
}
card = 1
for i in range (10):
    print(card[card])
    card = card+1

但这似乎没有帮助。这是我必须使用蛮力的东西，还是我缺少的更简单的方法？

编辑：抱歉，我在第二部分使用了一些错误的代码，现在已更新