将变量插入另一个新变量

Agiftel Longwave:

如何将变量插入正在创建的新变量中?我将之前创建的$ array [0]插入$ txt。我该怎么办?

问候

$conn = new mysqli("localhost","user","pass","db");
if ($conn->connect_error) {
  die("Connection failed: " . $conn->connect_error);
}

$sets   = "SELECT grp_phone FROM groups WHERE grp_onoff='YES'ORDER BY id ASC";

if ($result = mysqli_query($conn,$sets)){
    $array = array();
    while($r = mysqli_fetch_array($result))
        $array[] = $r[0];
        
   }

$group = fopen("/tmp/group_70000.txt", "w+") or die("Unable to open file!");
    $txt = 'SET Station_Group   "1": "1": "70000"
    {
    Attached_Stations = {".$array[0]"}
    }';
    fwrite($group, $txt);
    fclose($group);
$conn->close();```
Sfili_81:

随着{" '.$array[0] .' "}您得到您想要的价值。看一看

<?php

$array[0] = "100";//example

 $txt = 'SET Station_Group   "1": "1": "70000"
    {
    Attached_Stations = {" '.$array[0] .' "}
    }';
    
echo $txt;

你得到

SET Station_Group   "1": "1": "70000"
    {
    Attached_Stations = {" 100 "}
    }

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