根据列表中列表的大小返回两个列表

我有一个名为 scores

 [60, 60, 60, 60, 60, 57, 57, 57]

此外，我有一个 defaultdict，我all_scores_to_numerical_scores在其中存储飞镖投掷的所有数字分数。比如60，可以用三元组扔20/T20。30 可以用双 15 / D15 或 T10 打掉。

如果我输入

[all_scores_to_numerical_scores[score] for score in scores]

我得到以下输出

[['T20'], ['T20'], ['T20'], ['T20'], ['T20'], ['T19'], ['T19'], ['T19']]

但是，如果我的变量scores定义如下：

 [60, 60, 60, 30, 60, 57, 57, 57]

我得到

[['T20'], ['T20'], ['T20'], ['D15','T10'], ['T20'], ['T19'], ['T19'], ['T19']]

我应该如何更改我的代码以获取带有两个选项的列表，如下所示的两个列表

[['T20'], ['T20'], ['T20'], ['D15'], ['T20'], ['T19'], ['T19'], ['T19']]
[['T20'], ['T20'], ['T20'], ['T10'], ['T20'], ['T19'], ['T19'], ['T19']]

提前致谢，

获取 defaultdict 的附加信息：

import re
from collections import defaultdict

SCORES = ['D20', 'D19', 'D18', 'D17', 'D18', 'D17', 'D16', 'D15', 'D14', 'D13',
          'D12', 'D11', 'D10', 'D9', 'D8', 'D7', 'D6', 'D5', 'D4', 'D3', 'D2', 'D1',
          'S20', 'S19', 'S18', 'S17', 'S16', 'S15', 'S14', 'S13', 'S12', 'S11',
          'S10', 'S9', 'S8', 'S7', 'S6', 'S5', 'S4', 'S3', 'S2', 'S1', 'DB', 'SB',
          'T20', 'T19', 'T18', 'T17', 'T16', 'T15', 'T14', 'T13', 'T12', 'T11',
          'T10', 'T9', 'T8', 'T7', 'T6', 'T5', 'T4', 'T3', 'T2', 'T1']
 

def caculate_numerical_score(score: str) -> int:
   if score == 'DB':
      return 50
   elif score == 'SB':
      return 25
   elif score.startswith('T'):
      return 3 * int(re.findall('\d+', score)[0])
   elif score.startswith('D'):
      return 2 * int(re.findall('\d+', score)[0])
   else:
      return int(re.findall('\d+', score)[0])

if __name__ == "__main__":
   numerical_scores = {score: caculate_numerical_score(score) for score in SCORES}
   all_scores_to_numerical_scores = defaultdict(list)
   for score, numerical_score in numerical_scores.items():
      all_scores_to_numerical_scores[numerical_score].append(score)