我正在尝试在我的网站上进行投票和否决功能。但是有一个我不喜欢的特定行为，即每当用户单击按钮时，他都不应该重定向到另一个页面，而应该保留在同一页面上。
单击 upvote 按钮后会发生什么，它转到了http://localhost:8001/upvote/2/我不想要的 url 。我希望它保持在同一页面上http://localhost:8001/view-supplier/
模型.py
class User(AbstractBaseUser, PermissionsMixin):
email = models.EmailField(max_length=254, unique=True)
# CUSTOM USER FIELDS
firstname = models.CharField(max_length=30)
lastname = models.CharField(max_length=30)
upvotes = models.IntegerField(default=0)
downvotes = models.IntegerField(default=0)
objects = UserManager()
def get_absolute_url(self):
return "/users/%i/" % (self.pk)
def get_email(self):
return self.email
视图.py
def Viewsupplier(request):
title = "All Suppliers"
suppliers = User.objects.filter(user_type__is_supplier=True)
context = {"suppliers":suppliers, "title":title}
return render(request, 'core/view-suppliers.html', context)
@login_required
def upvote(request, pk):
supplier_vote = get_object_or_404(User, id=pk)
supplier_vote.upvotes += 1
supplier_vote.save()
upvote_count = supplier_vote.upvotes
context = {"supplier_vote":supplier_vote, "upvote_count":upvote_count}
return render(request, "core/view-suppliers.html", context)
@login_required
def downvote(request, pk):
supplier_vote = get_object_or_404(User, id=pk)
supplier_vote.downvotes -= 1
supplier_vote.save()
downvote_count = supplier_vote.downvotes
context = {"supplier_vote":supplier_vote, "downvote_count":downvote_count}
return render(request, "core/view-suppliers.html", context)
网址.py
from django.urls import path
from . import views
urlpatterns = [
path('upvote/<int:pk>/', views.upvote, name='upvote'),
path('downvote/<int:pk>/', views.downvote, name='downvote'),
]
查看供应商.html
<table class="table table-borderless table-data3">
<thead>
<tr>
<th>No</th>
<th>Country</th>
<th>Votes</th>
</tr>
</thead>
<tbody>
{% for supplier in suppliers %}
<tr>
<td>{{forloop.counter}}</td>
<td>{{supplier.country}}</td>
<td>
<div class="table-data-feature">
<a href="{% url 'upvote' supplier.id %}" class="m-r-10">
<button class="item" data-toggle="tooltip" data-placement="top" title="Like">
<i class="zmdi zmdi-thumb-up"></i>{{upvote_count}}</button>
</a>
<a href="{% url 'downvote' supplier.id %}">
<button class="item" data-toggle="tooltip" data-placement="top" title="Dislike">
<i class="zmdi zmdi-thumb-down"></i>{{downvote_count}}</button>
</a>
</div>
</td>
</tr>
{% empty %}
<tr><td class="text-center p-5" colspan="7"><h4>No supplier available</h4></td></tr>
{% endfor %}
</tbody>
</table>
您需要实现一个 API（应用程序编程接口）来异步发送赞成票和反对票。Django REST framework是创建您自己的 API 的方法。您可以在 YouTube 上观看有关该主题的数小时视频教程。Django REST framework 的文档非常好，也很容易阅读。Django 是一个服务器端的 web 框架，这意味着它只有在你提交到服务器时才能帮助你。您绝对可以重新加载同一页面：
return HttpResponseRedirect(reverse('<app_name>:<url_name>'))
但是，会有中断。因此，处理此类行为的推荐方法是使用 JavaScript 的 API（例如Fetch API）对 REST 框架进行异步调用。
如果您可能出于对学习异步编码的错误恐惧而决定以老式的方式将数据发送到您的服务器，您可以随时使用您的赞成和反对来提交用户数据并更新计数。然后，在您的 view_supplier 视图中，您需要获取更新的视图计数并将其传递给上下文。因此，您的 upvote 视图会更改 upvote 计数并触发 Viewsupplier 视图。然后，在 ViewSupplier 视图中，您获取计数并将其添加到上下文中
# in your template
<a href="{% url 'upvote' supplier.id %}" class="m-r-10">
<button class="item" data-toggle="tooltip" data-placement="top" title="Like">
<i class="zmdi zmdi-thumb-up"></i>{{upvote_count}}</button>
</a>
# in your view
def Viewsupplier(request):
title = "All Suppliers"
suppliers = User.objects.filter(user_type__is_supplier=True)
# Get the updated count:
suppliers_votes_count = {}
for supplier in suppliers:
upvote_count = supplier.upvotes
downvote_count = supplier.upvotes
supplier_count = {supplier: {'upvote': upvote_count, 'downvote': downvote_count } }
suppliers_votes_count.update(supplier_count)
context = {"suppliers":suppliers, "title":title, "suppliers_votes_count": suppliers_votes_count }
return render(request, 'core/view-suppliers.html', context)
@login_required
def upvote(request, pk):
supplier_vote = get_object_or_404(User, id=pk)
supplier_vote.upvotes += 1
supplier_vote.save()
upvote_count = supplier_vote.upvotes
context = {"supplier_vote":supplier_vote, "upvote_count":upvote_count}
return HttpResponseRedirect(reverse('core:view_supplier'))
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我来说两句