我想在这个项目上实现两个目标。首先,我想将登录用户另存为审阅者。其次,我想将外键中的律师价值传递给复查表。(通过这种方式,用户可以查看单击律师详细信息页面上的查看链接,然后查看该律师,而没有其他人。)
我不断犯错,这是我的第一个目标。
错误
IntegrityError at /lawyers/karlyn-rosemarie-hylton/review/
NOT NULL constraint failed: lawyers_review.reviewer_id
有人可以解释我在做什么错以及如何解决吗?
第二个目标似乎与第一个目标非常相关。我没有任何错误。但我想确保自己做得对。但是,直到我通过第一个错误,我才能告诉。
非常感谢任何帮助。
models.py
from django.db import models
from django.urls import reverse
from django.template.defaultfilters import slugify
from django.contrib.auth.models import User
class Lawyer(models.Model):
name = models.CharField(max_length=55,
default='')
picture = models.ImageField(upload_to='media/lawyers/pictures',
default='')
slug = models.SlugField()
def average_rating(self):
all_ratings = map(lambda x: x.rating, self.review_set.all())
return np.mean(all_ratings)
def save(self, *args, **kwargs):
self.slug = (slugify(self.name))
super(Lawyer, self).save(*args, **kwargs)
def get_absolute_url(self):
return reverse('lawyers:detail', kwargs={'slug': self.slug})
def __str__(self):
return self.name
class Review(models.Model):
RATING_CHOICES = (
(1, '1'),
(2, '2'),
(3, '3'),
(4, '4'),
(5, '5'),
)
lawyer = models.ForeignKey(Lawyer,
null=True)
created = models.DateTimeField(auto_now_add=True)
reviewer = models.ForeignKey(User)
title = models.CharField(max_length=55,
default='')
comment = models.TextField()
rating = models.IntegerField(choices=RATING_CHOICES)
def __str__(self):
return self.lawyer.name
views.py
from django.shortcuts import render, get_object_or_404
from django.views.generic import (CreateView,
DetailView,
ListView)
from django.contrib.auth.models import User
from .models import Lawyer, Review
class AddLawyerView(CreateView):
model = Lawyer
fields = ['name', 'picture']
def post_valid(self, form):
lawyer = form.save(Commit=False)
lawyer.picture = form.cleaned_data['picture']
return super(AddLawyerView, self).form_valid(form)
class LawyerDetail(DetailView):
model = Lawyer
class LawyerList(ListView):
model = Lawyer
class AddReviewView(CreateView):
model = Review
fields = ['rating', 'title', 'comment']
def post_valid(self, form):
review = form.save(Commit=False)
review.lawyer = get_object_or_404(Lawyer,
slug=self.kwargs.get('slug'))
review.reviewer = User.objects.get(user=self.request.user)
return super(AddReview, self).form_valid(form)
urls.py
from django.conf.urls import url
from .views import (AddLawyerView,
LawyerDetail,
LawyerList,
AddReviewView)
urlpatterns = [
url(r'^add-lawyer',
AddLawyerView.as_view(),
name = 'add-lawyer'),
url(r'^(?P<slug>[\w-]+)/$',
LawyerDetail.as_view(),
name = 'detail'),
url(r'^$',
LawyerList.as_view(),
name = 'list'),
url(r'^(?P<slug>[\w-]+)/review/$',
AddReviewView.as_view(),
name = 'add-review'),
]
利用@Alasdair和@Sachin Kukreja的反馈,我返回并进行了一些更正。我将“提交”更改为“提交”,将“ post_valid”更改为“ form_valid”。我还做了一个小调整,以简化视图。纠正和正常工作的AddReviewView如下。上面有一个错误。
谢谢你们!
工作视图:
class AddReviewView(CreateView):
model = Review
fields = ['rating', 'title', 'comment']
def form_valid(self, form):
review = form.save(commit=False)
review.lawyer = get_object_or_404(Lawyer,
slug=self.kwargs.get('slug'))
review.reviewer = self.request.user
return super(AddReviewView, self).form_valid(form)
您在那里有错别字,您处于压倒性状态,form_valid
但是您已经写了post_valid
。
def form_valid(self, form):
review = form.save(Commit=False)
review.lawyer = get_object_or_404(Lawyer,
slug=self.kwargs.get('slug'))
review.reviewer = User.objects.get(user=self.request.user)
# save and return HttpResponse
review.save()
return HttpResponseRedirect(self.get_success_url())
但是,该super
调用仍将调用父类,form_valid
这仍然会引发错误。我认为您可以将评论保存在此重写的方法中,并返回基类返回的内容,即return HttpResponseRedirect(self.get_success_url())
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