所以我有一个名为 'library' 的结构，它存储结构 'books' 的对象，并由 3 本书的列表初始化，但是当我尝试打印对象的属性时，我得到一个“分段错误（核心已转储） “ 错误。我知道这意味着我正在尝试访问一些我无权访问的内存，但在这种情况下我可以正确访问第一个元素，所以它让我相信我错误地初始化了一些东西。
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define MAXBOOKS 10
typedef struct books
{
char* title;
char* author;
int id;
}book;
typedef struct library
{
int number_of_books;
book* booklist [MAXBOOKS];
}lib;
void storeBook(lib library,book CurrentBook)
{
library.booklist[0] = &CurrentBook;
}
void printLibrary(lib library)
{
for(int i = 0; i < library.number_of_books; i++)
{
printf("Author:%s\n",library.booklist[i]->title);
}
}
int main()
{
book b_1 = {"The trial","Kafka",101};
book b_2 = {"The lurking fear","Lovecraft",102};
book b_3 = {"Dora's storytime collection","Valdes",103};
book* list = (book*)malloc(3*sizeof(book));
list[0] = b_1; list[1] = b_2; list[2] = b_3;
lib CurrentLibrary = {3,{list}};
printLibrary(CurrentLibrary);
return 0;
}
booklist1[i] = *(booklist1+i), 那么booklist2[i][j] = *(*(booklist2+i)+j), 如果j=0, 那么*(*(booklist2+i)+j) = *(*(booklist2+i)+0) = *(booklist2[i]) = *booklist2[i]
booklist2[0]指向第一行，booklist2[1]指向第二行，依此类推……等等。
您正在定义一个书本指针数组（二维数组）：book* booklist [MAXBOOKS]
但是list是一个书本数组（一维数组）。执行此语句后，lib CurrentLibrary = {3,{list}}; list数组将存储到booklist[0]行中。但是所有其他指针booklist[1], booklist[2],..... booklist[9]都没有指向任何元素。但是，你正在访问booklist[1]，booklist[2]以及booklist[3]在printLibrary功能。这就是分段错误的原因。
如需更多信息（对于二维数组），请打印以下几行：
printf("Title %s\n", library.booklist[0][0].title);版画-->标题审判printf("Title %s\n", library.booklist[0][1].title);版画-->标题潜伏的恐惧
printf("Title %s\n", library.booklist[0][2].title);版画-->标题朵拉的故事时间合集
但是尝试访问library.booklist[1][0].title会引发分段错误，因为第二行指针未指向任何元素。
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define MAXBOOKS 10
typedef struct books
{
char* title;
char* author;
int id;
}book;
typedef struct library
{
int number_of_books;
book *booklist; // It should be 1-D array, since you are passing 1-D array of book
}lib;
void storeBook(lib library,book CurrentBook)
{
library.booklist[0] = CurrentBook;
}
void printLibrary(lib library)
{
for(int i = 0; i < library.number_of_books; i++)
{
printf("Title:%s\n",library.booklist[i].title);
printf("Author:%s\n",library.booklist[i].author);
printf("Book ID:%d\n",library.booklist[i].id);
}
}
int main()
{
book b_1 = {"The trial","Kafka",101};
book b_2 = {"The lurking fear","Lovecraft",102};
book b_3 = {"Dora's storytime collection","Valdes",103};
book* list = malloc(3*sizeof(book));
list[0] = b_1; list[1] = b_2; list[2] = b_3;
lib CurrentLibrary = {3,list}; // list is 1-D array of book
printLibrary(CurrentLibrary);
return 0;
}
输出 ：
Title:The trial
Author:Kafka
Book ID:101
Title:The lurking fear
Author:Lovecraft
Book ID:102
Title:Dora's storytime collection
Author:Valdes
Book ID:103
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