java：非静态变量，不能从静态上下文中引用

genek 发表于 Dev

生殖器

我有错误Java：非静态变量，当在Man m1 = new Man（“ a1”，“ b1”，11）行中编译代码时，不能从静态上下文中引用它；如何解决？

public class Solution
{
public static void main(String[] args)
{
    //create two object of every class here
    Man m1 = new Man("a1", "b1", 11);
    Man m2 = new Man("a2", "b2", 12);
    Woman w1 = new Woman("a11", "b11", 13);
    Woman w2 = new Woman("a22", "b22", 14);

    //output them to screen here
    System.out.println(m1.name + " " + m1.age + " " + m1.address);
    System.out.println(m2.name + " " + m2.age + " " + m2.address);
    System.out.println(w1.name + " " + w1.age + " " + w1.address);
    System.out.println(w2.name + " " + w2.age + " " + w2.address);
}

//add your classes here
public class Man
{
    private String name;
    private String address;
    private int age;

    public Man(String name, String address, int age)
    {
        this.name = name;
        this.address = address;
        this.age = age;
    }
}
}

}

尼尔·阿尔法西

一种方法

将Man类声明为静态，您还可以从main()其中访问静态类（不与class的任何实例绑定Solution）：

public static class Man

另一种方法

我们还可以让类保持Man非静态状态，并创建一个实例级工厂方法，该方法将创建以下实例Man：

public class Solution {

    public static void main(String[] args) {
        //create two object of every class here
        Solution solution = new Solution();
        Man m1 = solution.createMan("a1", "b1", 11);
        Man m2 = solution.createMan( "a2", "b2", 12);

        //output them to screen here
        System.out.println(m1.name + " " + m1.age + " " + m1.address);
        System.out.println(m2.name + " " + m2.age + " " + m2.address);    
    }

    Man createMan(String name, String address, int age) {
        return new Man(name, address, age);
    }

    //add your classes here
    public class Man {
        private String name;
        private String address;
        private int age;

        private Man(String name, String address, int age) {
            this.name = name;
            this.address = address;
            this.age = age;
        }
    }
}

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