我想从一个Java源代码文件中删除所有类型的注释语句。例：
String str1 = "SUM 10" /*This is a Comments */ ;
String str2 = "SUM 10"; //This is a Comments"
String str3 = "http://google.com"; /*This is a Comments*/
String str4 = "('file:///xghsghsh.html/')"; //Comments
String str5 = "{\"temperature\": {\"type\"}}"; //comments
预期输出：
String str1 = "SUM 10";
String str2 = "SUM 10";
String str3 = "http://google.com";
String str4 = "('file:///xghsghsh.html/')";
String str5 = "{\"temperature\": {\"type\"}}";
我使用下面的正则表达式来实现：
System.out.println(str1.replaceAll("[^:]//.*|/\\\\*((?!=*/)(?s:.))+\\\\*/", ""));
这让我对STR4和STR5错误的结果。请帮我解决这个问题。
使用安德烈亚斯解决方案：
final String regex = "//.*|/\\*(?s:.*?)\\*/|(\"(?:(?<!\\\\)(?:\\\\\\\\)*\\\\\"|[^\\r\\n\"])*\")";
final String string = " String str1 = \"SUM 10\" /*This is a Comments */ ; \n"
+ " String str2 = \"SUM 10\"; //This is a Comments\" \n"
+ " String str3 = \"http://google.com\"; /*This is a Comments*/\n"
+ " String str4 = \"('file:///xghsghsh.html/')\"; //Comments\n"
+ " String str5 = \"{\"temperature\": {\"type\"}}"; //comments";
final String subst = "$1";
// The substituted value will be contained in the result variable
final String result = string.replaceAll(regex,subst);
System.out.println("Substitution result: " + result);
它除了STR5工作。
为了使它工作，你需要“跳过”字符串文字。您可以通过匹配字符串文字，捕捉他们，使他们可以保留这样做。
下面的正则表达式将做到这一点，利用$1作为替换字符串：
//.*|/\*(?s:.*?)\*/|("(?:(?<!\\)(?:\\\\)*\\"|[^\r\n"])*")
见regex101的演示。
Java代码则是：
str1.replaceAll("//.*|/\\*(?s:.*?)\\*/|(\"(?:(?<!\\\\)(?:\\\\\\\\)*\\\\\"|[^\r\n\"])*\")", "$1")
说明
//.* Match // and rest of line
| or
/\*(?s:.*?)\*/ Match /* and */, with any characters in-between, incl. linebreaks
| or
(" Start capture group and match "
(?: Start repeating group:
(?<!\\)(?:\\\\)*\\" Match escaped " optionally prefixed by escaped \'s
| or
[^\r\n"] Match any character except " and linebreak
)* End of repeating group
") Match terminating ", and end of capture group
$1 Keep captured string literal
本文收集自互联网，转载请注明来源。
如有侵权，请联系 [email protected] 删除。
我来说两句