有什么方法可以删除或替换EAssertionFailed错误消息的绝对路径吗?我不想包含整个路径,以不间接揭示源代码的编译位置并使消息独立于该位置。最好是,到项目根目录或DPR文件的相对路径或仅源文件名将包含在错误消息中。
程序输出:
EAssertionFailed: Assertion failed (C:\Users\User\Documents\
Embarcadero\Studio\Projects\Project3.dpr, line 12)
Project3.dpr
program Project3;
{$AppType Console}
{$R *.res}
uses
System.SysUtils;
begin
try
Assert(False);
except
on E: Exception do
begin
WriteLn(E.ClassName, ': ', E.Message);
ReadLn;
end;
end;
end.
替换或挂钩AssertErrorProc并更改或隐藏文件名和行号信息。
program Project1;
{$APPTYPE CONSOLE}
{$R *.res}
uses
System.SysConst,
System.SysUtils;
procedure CustomAssertErrorHandler(const Message, Filename: string; LineNumber: Integer; ErrorAddr: Pointer);
var
FileNameOnly : string;
begin
FileNameOnly := ExtractFileName(FileName);
if Message <> '' then
raise EAssertionFailed.CreateFmt(SAssertError,
[Message, FileNameOnly, LineNumber]) at ErrorAddr
else
raise EAssertionFailed.CreateFmt(SAssertError,
[SAssertionFailed, FileNameOnly, LineNumber]) at ErrorAddr;
end;
begin
AssertErrorProc := CustomAssertErrorHandler;
try
Assert(False);
except
on E: Exception do
begin
WriteLn(E.ClassName, ': ', E.Message);
ReadLn;
end;
end;
end.
更新:这是发问者的解决方案,它将完整的项目路径转换为相对路径:
program Project3;
{$AppType Console}
{$R *.res}
uses
System.SysConst,
System.SysUtils;
procedure AssertErrorHandler(const Msg, Filename: String;
LineNumber: Integer; ErrorAddr: Pointer);
{$Region '$Include ProjectRoot.pas.inc'}
const
ProjectRoot = 'C:\Users\';
{$EndRegion}
var
Temp: String;
begin
if (ProjectRoot <> '') and Filename.StartsWith(ProjectRoot) then
Temp := Filename.Remove(0, ProjectRoot.Length)
else
Temp := ExtractFileName(Filename);
if Msg <> '' then
raise EAssertionFailed.CreateResFmt(@SAssertError,
[Msg, Temp, LineNumber]) at ErrorAddr
else
raise EAssertionFailed.CreateResFmt(@SAssertError,
[SAssertionFailed, Temp, LineNumber]) at ErrorAddr;
end;
begin
try
AssertErrorProc := AssertErrorHandler;
// Assert(False);
Assert(False, 'Custom message');
except
on E: Exception do
begin
WriteLn(E.ClassName, ': ', E.Message);
ReadLn;
end;
end;
end.
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