将 char* 转换为 char [ ]

瓦拉迪斯瓦夫·库斯尼佐夫

你好亲爱的互联网 :D

所以我编写了一个“文本到莫尔斯”翻译器，效果很好。现在我想用 arduino 做同样的事情。莫尔斯电码应由闪烁的 LED 显示。我的问题是我有一个const char* morse[]={"....", ".-", ".-..", ".-..", "---"};我无法转换或重新分配给新变量char str[]以提供正确输出的 LED。

#include <stdio.h>
#include <string.h>
#include <ctype.h>

#define SHORT 2
#define LONG 3
#define PAUSE 800

char sentence[50]="Hello";
const char* morse[500];


const static char* letters[50]={"10","0111","0101","011","1","1101","001","1111","11","1000","010","1011","00","01","000","1001","0010","101","111","0","110","1110","100","0110","0100","0011"}; //A-Z

void setup(){
  pinMode(SHORT, OUTPUT);
  digitalWrite(SHORT, LOW);
  pinMode(LONG, OUTPUT);
  digitalWrite(LONG, LOW);
  Serial.begin(9600);
  all_Caps();
}

void loop(){
  all_Caps();
  int b=strlen(sentence);
    for(int i=0;i<b;i++)morse[i]=letters[sentence[i]-'A'];
  showtime();

  delay(PAUSE*10);
}


void all_Caps(){
  int b=strlen(sentence);
    for(int i=0;i<b;i++){
        sentence[i]= toupper(sentence[i]);
    }
}


void showtime(){
  
  char str[10];
  
  
  for(int i=0;i<10;i++){
    str=morse[i]; 
  }
  for(int e=0;e<10;e++){
    if(str[e]==1){
      digitalWrite(SHORT, HIGH);
      delay(50);
      digitalWrite(SHORT, LOW);
      delay(PAUSE);
    }
    else if(str[e]==0){
      digitalWrite(LONG, HIGH);
      delay(300);
      digitalWrite(LONG, LOW);
      delay(PAUSE);
    }
  }     
}

编辑：

所以我改变str=morse[i]对str[i]=morse[i]喜欢评论说。现在我收到警告信息：

sketch_aug05a.ino:48:19: warning: invalid conversion from 'const char*' to 'char' [-fpermissive]

0______

您不能分配字符串，这里不需要它

    for(int i=0;i<b;i++)
    {
        showtime(letters[toupper(sentence[i])-'A']);
    }

void showtime(const char *code)
{
    while(*code)
    {
        if(*code++ == '1')
        {
            digitalWrite(SHORT, HIGH);
            delay(50);
            digitalWrite(SHORT, LOW);
        }
        else
        {
            digitalWrite(LONG, HIGH);
            delay(300);
            digitalWrite(LONG, LOW);
        }
        delay(PAUSE);
    }
}

不需要全大写功能。

本文收集自互联网，转载请注明来源。

如有侵权，请联系 [email protected] 删除。