与字符串中的 sed 正则表达式匹配

我想将 stdout 命令中的字符串与 sed 和 regex 匹配

例如我有这个输出命令： connmanctl services ethernet_00142d000000_cable

这个输出：

Type = ethernet
  Security = [  ]
  State = ready
  Favorite = True
  Immutable = False
  AutoConnect = True
  Name = Wired
  Ethernet = [ Method=auto, Interface=eth0, Address=00:00:00:00:00:00, MTU=1500 ]
  IPv4 = [ Method=manual, Address=192.168.0.100, Netmask=255.255.255.0 ]
  IPv4.Configuration = [ Method=manual, Address=192.168.0.101, Netmask=255.255.255.0 ]
  IPv6 = [  ]
  IPv6.Configuration = [ Method=auto, Privacy=disabled ]
  Nameservers = [  ]
  Nameservers.Configuration = [  ]
  Timeservers = [  ]
  Timeservers.Configuration = [  ]
  Domains = [  ]
  Domains.Configuration = [  ]
  Proxy = [ Method=direct ]
  Proxy.Configuration = [  ]
  Provider = [  ]

我想eth0从Interface=eth0,（第 8 行）获取。

所以我使用这个命令： services ethernet_00142d000000_cable | sed -n -e 's/^.*Ethernet = //p' | sed -e 's/.*Interface=\([^,*]*\),*/\1/'

第一个 sed 使用以太网提取整行，第二个 sed 提取以 Interface 开头并以逗号结尾的字符串。

结果是：

eth0 Address=00:14:2D:00:00:00, MTU=1500 ]

为什么我在逗号后已经得到了以下内容。我怎么才能得到eth0？

谢谢你。